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2 years ago

Beginning with the flow phase, arrange the biochemical processes in the order in which they occur during the menstrual cycle.

Biology

1 answer:

vovikov84 [41]2 years ago

5 0

The biochemical processes in the order in which they occur during the menstrual cycle.

FSH and LH stimulate the follicles to develop and the oocyte to produce estrogen.
Rising estrogen levels suppress FSH production and the development of other follicles.
Elevated levels of progesterone maintain the endometrial lining of the uterus.
An LH surge causes the follicle to rupture.
The breakdown of the corpus luteum causes progesterone levels to drop.
The endometrial lining breaks down and low estrogen levels stimulate the pituitary gland to release FSH and LH.

<h3>How is the menstrual cycle regulated?</h3>

The menstrual cycle is regulated by the complex interaction of hormones: luteinizing hormone, follicle-stimulating hormone, and the female hormones estrogen and progesterone.

With this information, we can conclude that progesterone is a hormone that is responsible for regulating a woman's menstrual cycle, preparing the uterus to receive the fertilized egg and preventing it from being expelled by the body.

Learn more about menstrual cycle in brainly.com/question/27471285

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The number of cells in an average-sized adult human is on the order of 10^14 cells. Use this information, and the estimate that

KengaRu [80]

IF:
Number of cells: $C = 10^{14}$
DNA lenght: $D = 2m = 12.42 * 10^{-4} mi$
Distance from Earth to Sun: $ES=93000000 mi = 9.3* 10^{7}mi$

Then:
a) Over how many miles would the total DNA from the average human stretch?
The answer is product of multiplication of the number of cells (C) and the DNA length (D):
Total DNA: $T = C*D$
⇒ $T = 10^{14}*12.42* 10^{-4} mi$
⇒ $T = 12.42* 10^{14-4} mi$
⇒ $T = 12.42* 10^{10} mi$
The total DNA from the average human will stretch $12.42* 10^{10} mi$

b) How many times would the total DNA from the average human stretch from Earth to the Sun and back?
The answer is concluded from the ratio of the total DNA length (T) and the twice (because of stretch to the Sun and back, thus, two directions) of distance from Earth to the Sun (ES) and :
Ratio: $R= \frac{T}{2*ES}$
⇒ $R = \frac{12.42* 10^{10}mi }{2*(9.3* 10^{7}mi)}$
⇒ $R = \frac{12.42* 10^{10}}{18.6*10^{7}}$
⇒ $R = 0.6677* 10^{10-7}$
 ⇒ $R = 0.6677* 10^{3}$
 ⇒ [tex]R = 667.7
Thus, 667,7 times will the total DNA from the average human stretch from Earth to the Sun and back.

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3 years ago

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madreJ [45]

Answer:

A beast tbh

Explanation:

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3 years ago

Not all members of a species are the same. Every species exhibits

UkoKoshka [18]

Idk the options but it could be genetic variation

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4 years ago

In science why is it important to have more than one piece of evidence to support your claim?

My name is Ann [436]

Answer:

It is important to have more than one piece of evidence to make sure that the evidence is actually evidence. Or in other words, that the evidence is proven true. With only one piece of evidence, you can't be fully sure if calculations were correct, if the source was trustworthy, etc.

Multiple evidence is kinda like double checking math problems. If you don't do it, you can't be 100% certain the answer is correct.

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3 years ago

Which of the three tests included in McGill’s torso muscular endurance test battery is a timed test involving a static, isometri

tekilochka [14]

Answer:

Trunk flexor endurance test.

Explanation:

McGill’s torso muscular test is generally used to assess the muscle endurance of the torso muscles that works as a stabilizer. This test generally includes the four major test.

The test that includes the trunk flexor of the endurance test is a timed test that involves the static isometric contraction of the muscles. This test stabilizes the spine til the individual cannot hold the assumed position and the individual exhibits the fatigue.

Thus, the correct answer is option (A).

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3 years ago

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