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Elis [28]
2 years ago
13

If a balloon containing 0.342 moles of gas is left out in sun, the pressure is 1.54 atmospheres. If the temperature is 300 K, wh

at is the volume of the balloon? Note R is 8.314 L kPa mol-1K-1 or 0.821 L atm mol-1K-1 .
Chemistry
2 answers:
irina1246 [14]2 years ago
6 0

Answer:

1.2

Explanation:

Vilka [71]2 years ago
4 0

Answer:

54.7 L

Explanation:

To find the volume, you need to use the Ideal Gas Law. The formula looks like this:

PV = nRT

In this formula,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = number of moles

-----> R = constant (0.821 L*atm/mol*K)

-----> T = temperature (K)

You need to use the second R constant because the pressure is measured in atmospheres (atm) and not kPa. Because you have the all of the necessary variables except for volume, you can substitute them into the Ideal Gas Law formula and solve.

P = 1.54 atm                       R = 0.821 L*atm/mol*K

V = ? L                                T = 300 K

n = 0.342 moles

PV = nRT

(1.54 atm)V = (0.342 moles)(0.821 L*atm/mol*K)(300 K)

(1.54 atm)V = 84.2346

V = 54.7 L

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An atom of the element iron has an atomic number of 26 and an atomic weight of 56. if it is neutral, how many protons, neutrons,
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Proton 26
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3 0
3 years ago
A voltaic cell is constructed in which the cathode is a standard hydrogen electrode and the anode is a hydrogen electrode ()= 1a
Vinvika [58]

Explanation:

It is known that relation between E_{cell}, E^{o}_{cell}, and pH is as follows.

          E_{cell} = E^{o}_{cell} - (\frac{0.0591}{n}) \times log[H^{+}]


Also, it is known that E^{o}_{cell} for hydrogen is equal to zero.

Hence, substituting the given values into the above equation as follows.

     E_{cell} = E^{o}_{cell} - (\frac{0.0591}{n}) \times log[H^{+}]


         0.238 V = 0 - (\frac{0.0591}{1}) \times log[H^{+}] [/tex]

                  -log[H^{+}] = 4.03

                         [H^{+}] = antilog 4.03

                                           = 3.5

As, pH = -log[H^{+}].

Thus, we can conclude that pH of the given unknown solution at 298 K is 3.5.

4 0
3 years ago
Name the layers of earth in order from most dense to least dense.
Oksi-84 [34.3K]
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What are the characteristics shapes of s p and d orbitals
german

Answer:

Explanation:

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3 0
3 years ago
If a compound has a composition of 82% nitrogen and 18% hydrogen, what is the empirical formula for this compound
Damm [24]

Answer: The empirical formula for the given compound is NH_3

Explanation : Given,

Percentage of H = 18 %

Percentage of N = 82 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of H = 18 g

Mass of N = 82 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{18g}{1g/mole}=18moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{82g}{14g/mole}=5.8moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 5.8 moles.

For Hydrogen  = \frac{18}{5.8}=3.10\approx 3

For Nitrogen = \frac{5.8}{5.8}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of H : N = 3 : 1

Hence, the empirical formula for the given compound is NH_3

3 0
3 years ago
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