All categories

2 years ago

{f(x)=2x+1 g(x)=x2+2x−8

Mathematics

1 answer:

n200080 [17]2 years ago

8 0

The value of g(x) = 2[f(x)]² - 1 is g(x) = 8x² + 8x + 1

<h3>How to find a function?</h3>

f(x) = 2x+1

Find

g(x) = 2[f(x)]² - 1

Hence,

g(x) = 2[2x + 1]² - 1

g(x) = 2[4x² + 4x + 1] - 1

g(x) = 8x² + 8x + 2 - 1

g(x) = 8x² + 8x + 1

learn more on function here: brainly.com/question/1442153

#SPJ1

You might be interested in

Determine whether each mapping represents a function. Explain your reasoning.

FinnZ [79.3K]

Answer:

The first picture is a function and the second picture is not.

Step-by-step explanation:

Reason - In the first picture, there is no repeating value of x. In other words, every x value has a y value. However, in the second picture, the x value, 2 goes to 2 and -3.

4 0

3 years ago

What is the value expression for |-8|

Alenkinab [10]

Answer:

Step-by-step explanation:

8 0

3 years ago

What is the value of the expression (x-y)2 when x=5 and y=-1

rodikova [14]

(5- -1)2
(5+1)2
6x2
12

6 0

3 years ago

Simplify the expression -84 divided by 14

Nataliya [291]

easy peasy.

-84/14= -6

feel free to add me as a friend I am very good at math and am willing to help.

6 0

3 years ago

Select the correct expressions. 1 Identify each expression that represents the slope of a tangent to the curve y= * +1 at any po

Olegator [25]

The expressions which represents the slope of a tangent to the curve $y=\frac{1}{x+1}$ at any point (x, y) are:

$f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}$

<h3>The slope of a tangent to the curve.</h3>

Mathematically, the slope of a tangent line to the curve is given by this equation:

$f'(x) =limh \rightarrow 0\frac{f(x+h)-f(x)}{h}$

Given the function:

$f(x)=y=\frac{1}{x+1}$

When (x + h), we have:

$f(x+h)=y=\frac{1}{x+h+1}$

Next, we would find the derivative of f(x):

$f'(x) =limh \rightarrow 0\frac{\frac{1}{x+h+1} -\frac{1}{x+1}}{h}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -(x+h+1)}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -x-h-1}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}\\\\f'(x) = \frac{-1}{(x+1)(x+1)} \\\\f'(x) = \frac{-1}{(x+1)^2}$

Read more on slope of a tangent here: brainly.com/question/26015157

#SPJ1

5 0

2 years ago