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2 years ago

{f(x)=2x+1 g(x)=x2+2x−8

Mathematics

1 answer:

n200080 [17]2 years ago

8 0

The value of g(x) = 2[f(x)]² - 1 is g(x) = 8x² + 8x + 1

<h3>How to find a function?</h3>

f(x) = 2x+1

Find

g(x) = 2[f(x)]² - 1

Hence,

g(x) = 2[2x + 1]² - 1

g(x) = 2[4x² + 4x + 1] - 1

g(x) = 8x² + 8x + 2 - 1

g(x) = 8x² + 8x + 1

learn more on function here: brainly.com/question/1442153

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You and your friend get braces on the same day. You go for a checkup every fourth Tuesday. Your friend goes every third Tuesday.

Shtirlitz [24]

Answer: After 12 weeks they will both be at the dentists on the same Tuesday

Step-by-step explanation:

Since we have given that

He goes for a checkup every fourth Tuesday and his friend goes for a check up every third Tuesday.

We need to find the number of weeks they both will be at the dentist on the same Tuesday.

For this we will find "L.C.M. of 4 and 3 " =12

So, After 12 weeks they will both be at the dentists on the same Tuesday.

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3 years ago

What is the solution set for this inequality?

enyata [817]

Answer:

It's A

Step-by-step explanation:

You have to subtract 40 from both sides

Then divide both sides by 8

And then you have your answer.

8 0

3 years ago

Read 2 more answers

Helpppp pleaseeeeeeeeeeeeeee

Vesna [10]

Answer:

Find below the calculations of the two areas, each with two methods. The results are:

Upper triangle:

$Area=5000\sqrt{3}units^2$

Lower triangle:

$Area=14,530m^2$

Explanation:

A) Method 1

When you are not given the height, but you are given two sides and the included angle between the two sides, you can use this formula:

$Area=side_1\times side_2\times sin(\alpha)$

Where, $\alpha$ is the measure of the included angle.

1. Upper triangle:

$side_1=200units\\ \\ side_2=100units\\ \\ \alpha =60\º\\ \\ Area=200units\times 100units\times sin(60\º)/2\\ \\ Area=5000\sqrt{3}units^2$

2. Lower triangle:

$side_1=231m\\ \\ side_2=150m\\ \\ \alpha =123\º\\ \\ Area=231m\times 150m\times sin(123\º)/2\\ \\ Area=14,529.96m^2\approx14,530m^2$

B) Method 2

You can find the height of the triangle using trigonometric properties, and then use the very well known formula:

$Area=(1/2)\times base\times height$

Use it for both triangles.

3. Upper triangle:

The trigonometric ratio that you can use is:

$sine(\alpha)=opposite\text{ }leg/hypotenuse$

Notice the height is the opposite leg to the angle of 60º, and the side that measures 100 units is the hypotenuse of that right triangle. Then:

$sin(60\º)=height/100units\\ \\ height=sin(60\º)\times100units\\ \\ height=50\sqrt{3}units$

$Area=(1/2)\times base\times height=(1/2)\times 200units\times 50\sqrt{3}units=5,000\sqrt{3}units^2$

3. Lower triangle:

$sin(180\º-123\º)=height/231m\\ \\ height=sin(57\º)\times 231m\\ \\ height=193.7329m^2$

$Area=(1/2)\times base\times height=(1/2)\times 150m\times 193.7329m^2\\\\ Area=14,529.96m^2\approx 14,530m^2$

5 0

3 years ago

Which point on the line number line represntes -1/3

OverLord2011 [107]

Answer:

Point C

Happy Holidays!

5 0

3 years ago

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I need help with this (Image Attached)

NemiM [27]

Answer:

55,98,27

Step-by-step explanation:

To solve for the angles we must first find y with this equation

3y+5+2y-7=153

We can simplify this

5y-2=153

153+2=155

155/5=31

y=31

We now know y and can plug it into the angles

<A=2y-7

2(31)-7

62-7

<A=55

<B=3y+5

3(31)+5

93+5

<B=98

Now time for the last angle

Since angle BCA and DCB are next to each other they add up to 180

153+x=180

180-153=27

x=27

<BCA=27

4 0

3 years ago