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gizmo_the_mogwai [7]

3 years ago

15

What expression is equivalent to 3(x + 6)?

2 answers:

Bas_tet [7]3 years ago

6 0

Answer:

3x+18

Step-by-step explanation:

Marina86 [1]3 years ago

5 0

3x+18

hope this helps

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Find the product. 3(m n)

Mkey [24]

<span>product. 3(m n) = 3mn</span>

5 0

3 years ago

Nvmm lzodjiofjewkifjf

hoa [83]

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3 0

3 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

3 years ago

CAN SOMEONE PLEASE HELL ME WITH THIS PROBLEM? THANK YOU!!!

Verizon [17]

Answer:

71

Step-by-step explanation:

The reference angle is always the smallest angle with the x-axis.

The nearest x axis is at 0 or another name for 0 is 360

360 -289 = 71

The reference angle is 71

8 0

2 years ago

Law of cosines.Anyone good in Trigonometry?

marin [14]

Answer:

$c=11.8\ units$

Step-by-step explanation:

we know that

The formula of law of cosines is equal to

$c^2=a^2+b^2-2(a)(b)cos(C)$

where

a, b and c are sides. C is the angle opposite side c

In this problem we have

$a=3\ units\\b=10\ units$

$C=120^o$

substitute the given values

$c^2=3^2+10^2-2(3)(10)cos(120^o)$

$c^2=109-(60)cos(120^o)$

$c^2=109-(60)(-0.5))$

$c^2=109+30$

$c^2=139$

$c=11.8\ units$

3 0

3 years ago