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ohaa [14]
2 years ago
11

Solve this equation -1/2 ( -3y + 10)

Mathematics
2 answers:
stiv31 [10]2 years ago
7 0
The person above me’s answer is correct
mr_godi [17]2 years ago
6 0

Answer:

3/2y-5

Step-by-step explanation:

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3. Which statements about the line that passes through (-2, 0) and (2, -4) are true?
diamong [38]

Answer:

B, C, and D.

Step-by-step explanation:

Let's go through each answer choice.

A: To find the slope of a line from two points, we use this formula: (y_2-y_1)/(x_2-x_1). Plugging in the values (-2,0) and (2, -4), we get:

  • (-4-0)/(2+2)
  • -4/4
  • -1

Because option A says the slope is 1, but we got -1, option A is false.

B: To find the y-intercept, we use this formula: b = y_1 - m * x_1

  • b = 0 -(-1) * (-2)
  • b = 1 * (-2)
  • b = -2  

Since we know the value of b is the y-intercept, we could write the y-intercept as (0,-2). Therefore, option B is true.

C: The equation of a line (in slope-intercept form) is y = mx + b, where y - y-coordinate, m = slope, x = x-coordinate, and b = y-intercept. Since we already solved for the y-intercept and slope, let's plug in those values:

  • y = mx +b
  • y = -x -2

As you can see, the equation we got here matches the one in option C, meaning it's true.

D: We know that a point is written like this: (x, y). If the x-coordinate is not zero but the y-coordinate is, then it's the x-intercept. Since the question says that (-2,0) is one of the points the line passes through, and option D says that the x-intercept is (-2,0), it's true.

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Answer:

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Step-by-step explanation:

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At noon, ship A is 180 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 25 km/h. How fast is
weeeeeb [17]

Answer:

Step-by-step explanation:

Gotta love these motion  problems!!! This one  is especially tricky!  At noon, ship A is 180 km west of ship B.  If ship A is traveling east, it is closing its distance to ship B (if ship B didn't move).  But ship B is moving north at the same time.  We need to find the distance each can travel in 4 hours using the d = rt formula.  For ship A.  We know it's moving at 35 km/h, so in 4 hours it can move d = 35(4) which is 140 km.  Remember that is closing the distance to ship B.  So it is 180 - 140 directly south of ship B.  This problem will turn out to be a right triangle problem of sorts.  The distance of 40 km serves as the base of this right triangle.  

With ship B moving north at 25 km/hr, it can travel d = 25(4) which is 100 km.  This serves as the height of the triangle.  We are asked to find the rate at which the distance is changing 4 hours from their starting points.  We know how far each can travel in those 4 hours, so in order to find the rate of change (which is the same thing as the slope!), we take the height and divide it by the base because that is the same thing as taking the rise over the run.  100/40 is 10/4 which is a rate of change of 2.5 km/hr

5 0
3 years ago
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