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Charra [1.4K]
3 years ago
5

4. DE is the perpendicular bisector of JL. Which statement must be true?

Mathematics
2 answers:
ZanzabumX [31]3 years ago
7 0

Since DE is the perpendicular bisector of JL.

The perpendicular bisector is a line that divides a line segment into two equal parts. It also makes a right angle with the line segment. Each point on the perpendicular bisector is the same distance from each of the endpoints of the original line segment.

Since, a perpendicular bisector is a line that divides a line segment into two equal parts.

So, JK=KL. (which is not given in the option)

Since ED is a perpendicular bisector. So, each point on ED is the same distance from the endpoints of line segment JL.

So, EJ=EL.

Therefore, Option 1 is the correct answer.

Alexeev081 [22]3 years ago
5 0
Did you ever get the answer? I think it is A
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If f x is a linear function, f(-1)=3, and f(1)=5, find an equation for f(x)
BartSMP [9]

The equation of f(x) is f(x) = x + 4

<h3>How to determine the equation?</h3>

The given parameters are

f(-1) = 3 and f(1) = 5

Start by calculating the slope (m) using:

m = \frac{f(1) - f(-1)}{1 - -1}

This gives

m = \frac{5 - 3}{1 + 1}

Evaluate

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The equation is then calculated as;

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This gives

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Expand

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1 year ago
Using interval notation, the domain off is [- 3, 5] and the domain of g is [- 2, 7] . On what domain is f defined
Scorpion4ik [409]

Note: I am assuming you mean ''on what domain is f+g is defined''.

Answer:

We conclude that

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Step-by-step explanation:

Given the domain of f

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Given the domain of g

[-2, 7]

  • The domain of a composition f+g would include the intersection of both domains.

In other words, the domain of a composition f+g includes all the inputs of x-values that are in the domain of both functions i.e. f and g.

so

Domain of f = [-3, 5]

The x-values lie in the domain of f interval are:

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Domain of g = [-2, 7]

The x-values lie in the domain of g interval are:

x = -2, 1, 0, 1, 2, 3, 4, 5, 6, 7

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