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Alborosie
3 years ago
10

I really need help what's the answer??

Mathematics
1 answer:
lys-0071 [83]3 years ago
5 0
I think you just have to add all of the totals up??
You might be interested in
1/3y+1/4=5/12 i need 20 character
lys-0071 [83]
Y/3 + 1/4 = 5/12
4y/12 + 3/12 = 5/12
           4y/12 = 2/12
                4y = 2
                /4     /4
                  y = 1/2

Therefore y = 1/2

3 0
3 years ago
-2(-2x + 3)-x -1 = -28
vekshin1

Answer:

x = -1

Step-by-step explanation:

I hope it helps u dear

5 0
2 years ago
Read 2 more answers
Before the distribution of certain statistical software, every fourth compact disk (CD) is testedfor accuracy. The testing proce
pishuonlain [190]

Answer:

P(T∩E) = 0.017

Step-by-step explanation:

Since every fourth CD is tested. Thus if T is the event that represents 4 disks being tested,

P(T) = 1/4 = 0.25

Let Fi represent event of failure rate. So from the question,

P(F1) = 0.01 ; P(F2) = 0.03 ; P(F3) =0.02 ; P(F4) = 0.01

Also Let F'i represent event of success rate. And we have;

P(F'1) = 1 - 0.01 = 0.99 ; P(F'2) = 1 - 0.03 = 0.97; P(F'3) = 1 - 0.02 = 0.98; P(F'4) = 1 - 0.01 = 0.99

Since all programs run independently, the probability that all programs will run successfully is;

P(All programs to run successfully) =

P(F'1) x P(F'2) x P(F'3) x P(F'4) =

0.99 x 0.97 x 0.98 x 0.97 = 0.932

Now, that all 4 programs failed will be = 1 - 0.932 = 0.068

Let E be denote that the CD fails the test. Thus P(E) = 0.068

Now, since testing and CD's defection are independent events, the probability that one CD was tested and failed will be =P(T∩E) = P(T) x P(E)= 0.25 x 0.068 = 0.017

8 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Yakvenalex [24]

Answer: (C) even

<u>Step-by-step explanation:</u>

A function is even when f(x) = f(-x)

A function is odd when f(-x) = -f(x)


f(x) = -2x⁴ + 3x²

f(-x) = -2(-x)⁴ + 3(-x)²

      = -2x⁴ + 3x²

f(x) = f(-x) so the function is even


-f(x) = -(-2x⁴ + 3x²)

       = 2x⁴ - 3x²

f(-x) ≠ -f(x) so the function is not odd.

8 0
3 years ago
Every day for 5 days Jack and Jill went walking. Each day Jack walked 4/5 of a mile and Jill walked 2/3 of a mile. At the end of
DanielleElmas [232]

\bf \stackrel{\textit{Jack for 7 days}}{7\left( \cfrac{4}{5} \right)}\implies \cfrac{28}{5}~\hspace{10em}\stackrel{\textit{Jill for 7 days}}{7\left( \cfrac{2}{3} \right)}\implies \cfrac{14}{3}&#10;\\\\[-0.35em]&#10;~\dotfill\\\\&#10;\cfrac{28}{5}-\cfrac{14}{3}\implies \stackrel{\textit{LCD of 15}}{\cfrac{(3)28-(5)14}{15}}\implies \cfrac{84-70}{15}\implies \cfrac{14}{15}

7 0
3 years ago
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