<img src="https://tex.z-dn.net/?f=x%5E%7B8%7D%2Bx%5E%7B4%7D%2B1" id="TexFormula1" title="x^{8}+x^{4}+1" alt="x^{8}+x^{4}+1" alig

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Neporo4naja [7]

2 years ago

8

n="absmiddle" class="latex-formula">

1 answer:

ella [17]2 years ago

6 0

You did not provide directions. What do you want us to do with your 8th degree polynomial?

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2x+8.4=2.634+5.42x <br><br>round to the nearest thousandth

Natasha2012 [34]

x= 1.68596491

So just round that number and you have your answer.

3 0

3 years ago

Need help please with this question.

GalinKa [24]

The second one is it

3 0

3 years ago

Please help me with 1,2,3,4 and show me how you get it the answers

Dafna11 [192]

Answer:

Step-by-step explanation:

Use the formula of distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ ,

Distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

1. Distance between A(3, 4) and B(8, 12),

AB = $\sqrt{(8-3)^2+(12-4)^2}$

AB = $\sqrt{25+64}$

= $\sqrt{89}$

≈ 9.43

2. Distance between C(-2, 10) and D(3, -2),

CD = $\sqrt{(3+2)^2+(-2-10)^2}$

= $\sqrt{25+144}$

= $\sqrt{169}$

= 13.00

3. Distance between X(20, 4) and Y(17, 0),

XY = $\sqrt{(20-17)^2+(4-0)^2}$

= $\sqrt{3^2+4^2}$

= $\sqrt{25}$

= 5.00

4. Distance between E(2, -1) and M(6, 9),

EM = $\sqrt{(2-6)^2+(-1-9)^2}$

= $\sqrt{16+100}$

= $\sqrt{116}$

= 10.77

8 0

3 years ago

What is the remainder R when the polynomial p(x) is divided by (x + 1)? Is (x + 1) a factor of p(x)? p(x) = -3x4 + 2x3 - x2 + 6

vodka [1.7K]

Answer:

(x+1) is a factor with remainder 0.

Step-by-step explanation:

We divide (x+1) into the polynomial $-3x^4+2x^3-x^2+6$ through long division or synthetic. We choose long division and look for what will multiply with (x+1) to make the polynomial $-3x^4+2x^3-x^2+6$ .

$(x+1)(-3x^3)=-3x^4-3x^3$

We subtract this from the original $-3x^4-(-3x^4)+2x^3-(-3x^3)-x^2+6$ .

This leaves $5x^3-x^2+6$ . We repeat the step above.

$(x+1)(5x^2)=5x^3+5x^2$ .

We subtract this from $5x^3-(5x^3)-x^2-(5x^2)+6=-6x^2+6$ . We repeat the step above.

$(x+1)(-6x)=-6x^2-6x$ .

We subtract this from $-6x^2-(-6x^2)+0x-(-6x)+6=6x+6$ . We repeat the step above.

$(x+1)(6)=-6x+1$ .

We subtract this from $6x-(6x)+6-(6)=0$ . There is no remainder. This means (x+1) is a factor.

7 0

3 years ago

Complete the sequence of numbers in the set. Explain the pattern.

Firdavs [7]

It’s -0.45 and the next to numbers are 5.35 and 4.9

8 0

3 years ago