A.
F(10)= (10)^2-3(10)-5
F(10)=100-30-5
F(10)=65
B.
F(-3)=(-3)^2-3(-3)-5
F(-3)=9+9-5
F(-3)=13
C.
G(2)= -6(2)+1
G(2)= -12+1
G(2)=-11
D.
G(10)=-6(10)+1
G(10)= -60+1
G(10)= -59
A cause she measured the side of it
I hope this helps you
t=r/r-3
t. (r-3)=r
t.r-3t=r
t.r-r=3t
r (t-1)=3t
r=3t/t-1
Answer:
C. Are all real numbers greater than or equal to -8.
Step-by-step explanation:
Real numbers can be said to be all continuous values of quantity, which can be negative or positive values.
The range of h, h(x), in the table given are all real numbers.
The least of the range of h on the table is -8. All the other range values, namely, -7, 1, 17, and 41 are all greater than -8. None is less than -8.
Therefore, we can conclude that the range values of h "are all real numbers greater than or equal to -8".
Answer:
Part one: The function rule for the area of the rectangle is A(x) = 3x² - 2x
Part two: The area of the rectangle is 8 feet² when its width is 2 feet
Step-by-step explanation:
Assume that the width of the rectangle is x
∵ The width of the rectangle = x feet
∵ The length of the rectangle is 2 ft less than three times its width
→ That means multiply the width by 3, then subtract 2 from the product
∴ The length of the rectangle = 3(x) - 2
∴ The length of the rectangle = (3x - 2) feet
∵ The area of the rectangle = length × width
∴ A(x) = (3x - 2) × x
→ Multiply each term in the bracket by x
∵ A(x) = x(3x) - x(2)
∴ A(x) = 3x² - 2x
∴ The function rule for the area of the rectangle is A(x) = 3x² - 2x
∵ The rectangle has a width of 2 ft
∵ The width = x
∴ x = 2
→ Substitute x by 2 in A(x)
∵ A(2) = 3(2)² - 2(2)
∴ A(2) = 3(4) - 4
∴ A(2) = 12 - 4
∴ A(2) = 8
∴ The area of the rectangle is 8 feet² when its width is 2 feet
