All categories

3 years ago

Chandra wishes to reduce has mass by 6% in a month's time if his mass is 80 kg now what should his mass in a month's time Be?

Mathematics

1 answer:

Arturiano [62]3 years ago

7 0

Answer:

75.2 kg

Step-by-step explanation:

His mass now is 80 kg which is 100% of his mass since 100% is the entire amount. He wishes to reduce his mass by 6%.

100% - 6% = 94%

After reducing his mass by 6%, his mass will become 94% of his original mass, 80 kg.

We need to find 94% of 80 kg.

94% of 80 kg = 94% × 80 kg = 0.94 × 80 kg = 75.2 kg

You might be interested in

Help!! BRAINLIEST TOO!

natulia [17]

Answer:

36.5 inches

Step-by-step explanation:

Given

See attachment for the given data

Required

Which length is closest to 4.2lb

The given data is a linear dataset.

So, we start by calculating the slope (m)

$m =\frac{y_2 - y_1}{x_2 - x_1}$

Pick any two corresponding points from the table

So, we have:

$(x_1,y_1) = (8,1.21)$

$(x_2,y_2) = (12,1.63)$

So:

$m =\frac{y_2 - y_1}{x_2 - x_1}$

$m =\frac{1.63 - 1.21}{12 - 8}$

$m =\frac{0.42}{4}$

$m =0.105$

The linear equation is then calculated using:

$y = m(x - x_1) + y_1$

This gives:

$y = 0.105 * (x - 8) + 1.21$

Open bracket

$y = 0.105x - 0.84 + 1.21$

$y = 0.105x + 0.37$

To get the length closest to 4.2lb,

we set $y = 4.2$

Then solve for x

So, we have:

$y = 0.105x + 0.37$

$4.2 = 0.105x + 0.37$

Collect like terms

$0.105x= 4.2 - 0.37$

$0.105x= 3.83$

Solve for x

$x= 3.83/0.105$

$x\approx 36.5$

4 0

3 years ago

What is the common ratio for this geometric sequence?

Anastasy [175]

Answer:

Step-by-step explanation:

$\text{The common ratio of a geometric sequence}\ a_n:\\\\r=\dfrac{a_{n+1}}{a_n}\\\\\text{We divide next term by the previous one.}\\\\r=\dfrac{9}{27}=\dfrac{9:9}{27:9}=\dfrac{1}{3}\\\\r=\dfrac{3}{9}=\dfrac{3:3}{9:3}=\dfrac{1}{3}\\\\r=\dfrac{1}{3}\\\vdots$