If ages are normally distributed then using a significance level of 0.05 , we can claim that the population mean is greater than 24.
Given sample mean of 25 years , sample size of 16 ,standard deviation of 2 years.
We have to find whether the population average is greater than 24.
We have to use t test because n is less than 30. It is right tailed.
We have to first form Hypothesis.
:μ>24,
:μ<24.
t=X-μ/S/
t critical at 5% significance level and degree of freedom=15 (16-1)=1.7531
t=24-25/2/
=-1/0.5
=-2
Because 1.7531 is greater than -2 so we will accept the null hypothesis.
Hence we can say that the average of population is greater than 24.
Learn more about t test at brainly.com/question/6589776
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Answer:
Using Pythagorean theorem:
Diagonal = sqrt( 60^2 + 100^2) = 116.62
Hope this helps!
:)
When p is down 7 units you are just going to go up
First you make them fractions that have the same denominator. 12 can be the denominator, because 6 5/12 already has that denominator and to get 2 2/3 to have a denominator of 12, you multiply the numerator and denominator by 4 (3•4=12, but you have to do the same thing to the top and bottom of the fraction). You then have the equation
6 5/12- 2 8/12. Since you cant subtract 8/12 from 5/12, you turn the numbers into improper fractions, which would be
77/12 - 32/12. You subtract them and get 45/12. You then have to simplify it again, 12 can go into 45, 3 times and you would have 3 and 9/12. 9/12 can be simplified down to 3/4. So the answer would be 3 3/4.
Answer:
<h3>x = Pn</h3>
Step-by-step explanation:
Cross Multiply
