All categories

2 years ago

Place value in the thousands for the 0 in 10000

Mathematics

1 answer:

horsena [70]2 years ago

3 0

The place value in the thousands for the 0 in 10,000 is three (3).

<h3>What is a place value?</h3>

A place value refers to a numerical value which denotes a digit based on its position in a given number and it includes:

Tenths

Hundredths

Thousandths

Unit

Tens

Hundreds

Thousands

In this scenario, the place value in the thousands for the 0 in 10,000 is three (3).

Read more on place value here: brainly.com/question/2003695

#SPJ1

You might be interested in

What is the length of the focal width?<br><br> x^2=12y

Ierofanga [76]

$\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})} \\\\
(x-{{ h}})^2=4{{ p}}(y-{{ k}}) \\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}\\\\
4p=focal\ width
\end{array}\\\\
-------------------------------\\\\
x^2=12y\implies (x-0)^2=12(y-0)\quad 
\begin{cases}
h=0\\
k=0\\
\boxed{4p=12}
\end{cases}$

3 0

3 years ago

Read 2 more answers

The number of calories in a piece of pie is 20 less than three times the number of calories in a scoop of ice cream. The pie and

sergejj [24]

Answer:

130 calories in the ice cream and 500 calories in the pie.

Step-by-step explanation:

Let the amount of calories in the scoop of ice cream be x. the amount of calories in the piece of pie be 3x-20. we know that x+3x-20=500.

4x-20=500

If we add twenty to both sides, we end up with:

4x=520

Divide both sides by four, and you get x=130.

there are 130 calories in the scoop of ice cream and 130*4-20=500 calories in the pie.

5 0

3 years ago

Pls help I have no idea what the answer is

Lena [83]

Answer:

Step-by-step explanation:

x/5=5/2

x=25/2

x=12.5

6 0

3 years ago

Point (k, -3) lies on the line whose equation is x-2y=-2. What is the value of k?

natita [175]

Answer:

Substitute, <em><u>y = -3</u></em> and <em><u>x = k</u></em> on the equation.

=> k - 2×(-3) = -2

=> k = -2 + (-6)

=> k = - 8

=================

<h2>HOPE U UNDERSTOOD</h2><h3>MARK AS BRAINLIEST ONE</h3>

Any Doubts? Please COMMENT

7 0

3 years ago

At NC State University, 16.4% of the undergraduate classes have more than 50 students. If a random sample of 200 undergraduate c

Lena [83]

Answer:

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=200, p=0.164)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

6 0

3 years ago