Question

What is the length of the focal width? x^2=12y

Answer 1

Answer:

The length of the Focal Width is 12

Step-by-step explanation:

Apex

Answer 2

$\bf \textit{parabola vertex form with focus point distance}\\\\ \begin{array}{llll} \boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})} \\\\ (x-{{ h}})^2=4{{ p}}(y-{{ k}}) \\ \end{array} \qquad \begin{array}{llll} vertex\ ({{ h}},{{ k}})\\\\ {{ p}}=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ 4p=focal\ width \end{array}\\\\ -------------------------------\\\\ x^2=12y\implies (x-0)^2=12(y-0)\quad \begin{cases} h=0\\ k=0\\ \boxed{4p=12} \end{cases}$