Answer:
2. ![\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C0%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
3. ![\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%2621%2660%5C%5C-15%269%26-45%5C%5C%5Cend%7Barray%7D%5Cright%5D)
4. ![\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-14%5C%5C-2%26-6%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
2. This matrix is easy, as it just requires addition.
+ ![\left[\begin{array}{ccc}0&0\\0&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
3. This matrix requires for the matrices to be multiplied first, then added.
![\left[\begin{array}{ccc}9&-15&18\\-27&15&-9\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-15%2618%5C%5C-27%2615%26-9%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}-12&36&42 \\12& -6 & -36 \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-12%2636%2642%20%5C%5C12%26%20-6%20%26%20-36%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
4. Here we can add the last 2 matrices to find x.
![\left[\begin{array}{ccc}2&-8\\-4&2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-8%5C%5C-4%262%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}4&-6\\2&-8 \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-6%5C%5C2%26-8%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
Hope this helps! (Please consider giving brainliest)
Answer:x=100
Step-by-step explanation:
Since you know that g(x)=3x-11 all you have to do is substitute that into g(x)=289. So you get 3x-11=289. To get x you have to add 11 on both sides.
3x-11=289
+11 +11
----------------
3x = 300
Divide 3 on both sides to get x by itself
3x =300
---- -------
3 3
x=100
To find it, evaluate it at the endpoints and the vertex
in form
f(x)=ax²+bx+c
the x value of the vertex is -b/2a
given
c(t)=1t²-10t+76
x value of vertex is -(-10)/1=10
evaluate c(0) and c(13) and c(10)
c(0)=76
c(13)=115
c(10)=76
it reached minimum in 2000 and 2010
porbably teacher wants 2010
the min value is $76
Answer:
x=sqrt(y+2), -sqrt(y+2)
Step-by-step explanation:
y=x^2-2
x^2=y+2
x=sqrt(y+2), -sqrt(y+2)
Answer:
32
Step-by-step explanation:
32 is the GCF of the whole numbers and up to x2 can go into both
The answer should be 32x2
Hope this helps
