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aleksandrvk [35]
3 years ago
14

Using the punnett square below, choose the probability that the recessive trait will be present in the offspring.

Mathematics
1 answer:
Licemer1 [7]3 years ago
5 0

Answer:

50%

Step-by-step explanation:

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Can anyone help me with this?
mestny [16]

Answer:

x = 12

Step-by-step explanation:

they are virtical menaing they are the same value

6x + 7 = 8x - 17

6x + 24 = 8x

24 = 2x

12 = x

8 0
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Mariana [72]

Answer:

third one

Step-by-step explanation:

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4 years ago
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Select the correct answer.
vekshin1
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4 0
3 years ago
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5) A data set with whole numbers has a low value 20 and high value of 82. Find the class width and class limits for a frequency
Gre4nikov [31]

Answer:

Class width = 9

Class limits = 20 - 28; 20 - 28; 29 - 37; 38 - 46; 47 - 55; 56 - 64; 65 - 73; 74 - 82.

Step-by-step explanation:

We are given;

Highest value = 82

Lowest value = 20

Frequency = 7

Formula for class width is;

Class width = (Highest Value - Lowest Value)/number of classes

Class width = (82 - 20)/7

Class width = 8.8 ≈ 9

Now,since class width is 9, limits between 20 and 82 would be done at intervals of 9.

Thus;

Class limits = 20 - 28; 20 - 28; 29 - 37; 38 - 46; 47 - 55; 56 - 64; 65 - 73; 74 - 82.

6 0
3 years ago
I need help with my algebra 2. I also want to know how to solve this.
Lisa [10]

Add 1 to both sides:

\sqrt{x+3} = x+1

In cases like this, we have to remember that a root is always positive, so we can square both sides only assuming that

x+1 \geq 0 \iff x \geq -1

Under this assumption, we square both sides and we have

x+3 = (x+1)^2 \iff x+3 = x^2+2x+1 \iff x^2+x-2 = 0

The solutions to this equation are

x = -2,\ x=1

But since we can only accept solutions greater than -1, we discard x=-2 and accept x=1.

In fact, we have

x=-2 \implies \sqrt{-2+3}-1=0\neq -2

and

x=1 \implies \sqrt{4}-1=1

which is the only solution.

4 0
4 years ago
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