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nexus9112 [7]
2 years ago
13

An artist plans to sell $250 of prints online each week. This month, she is within $25 of her goal.

Mathematics
1 answer:
tiny-mole [99]2 years ago
3 0

The absolute value equation to represent the scenario is |x - 250| = 25. Also, the minimum amounts and maximum amounts that the artist received for her products is $225 and $275 respectively.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the amount the artist can receive for the goods, hence:

|x - 250| = 25

x - 250 = 25 or -(x - 250) = 25

x = 275 or x = 225

The absolute value equation to represent the scenario is |x - 250| = 25. Also, the minimum amounts and maximum amounts that the artist received for her products is $225 and $275 respectively.

Find out more on equation at: brainly.com/question/2972832

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Damm [24]

Answer:

y = 2x + 0 or y = 2x

Step-by-step explanation:

use slope-intercept form \frac{y2 - y1}{x2 - x1}

12 - 10 = 2

6 - 5 = 1

m value = 2/1 = 2

y=2x+b

to find b plug one of the points in for x and y

Example: 10 = 2(5) + b

solve equation

10 = 10 + b

subtract 10 from both sides

0 = b

Equation of line equals y=2x+0 or simply just y=2x

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Let P = 0.50.30.50.7 be the transition matrix for a Markov chain with two states. Let x0 = 0.50.5 be the initial state vector fo
pav-90 [236]

Answer:

Probability distribution vector = \left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)

Step-By-Step Explanation

If P=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right)  is the transition matrix for a Markov chain with two states.  

x_{0}=\left(\begin{array}{c}0.5\\ 0.5 \end{array} \right)  be the initial state vector for the population.

X_{1}=P x_{0}=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right) \left(\begin{array}{c}0.5\\ 0.5 \end{array} \right) =\left(\begin{array}{c}0.4\\ 0.6 \end{array} \right)  

X_{2}=P^{2} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)  

X_{3}=P^{3} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)  

X_{30}=P^{30} x_{0}=\left(\begin{array}{c}0.37499\\ 0.625 \end{array} \right)  

In the long run, the probability distribution vector Xm approaches the probability distribution vector \left(\begin{array}{c}0.375\\ 0.625 \end{array} \right) .

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Given:

The given equation is:

y=-4x+3

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