Answer:
<em>150 miles</em>
Step-by-step explanation:
Given the scale on the map using the conversion factor
1 inch = 50 miles
We are to find the equivalent miles between the cities in miles if the distace is 3inches
3inches = x
Divide both expressions
1/3 = 50/x
Cross multiply
x = 3 * 50
x = 150
<em>Hence the actual distance between these two cities in miles is 150 miles </em>
Area of the figure = 30.28 m²
Solution:
The given image is splitted into two shapes.
One is rectangle and the other is semi-circle.
Length of the rectangle = 6 m
Width of the rectangle = 4 m
Area of the rectangle = length × width
= 6 m × 4 m
= 24 m²
Area of the rectangle = 24 m²
Diameter of the semi-circle = 4 m
Radius of the semi-circle = 4 m ÷ 2 = 2 m
Area of the semi-circle = 


Area of the semi-circle = 6.28 m²
Area of the figure = Area of the rectangle + Area of the semi-circle
= 24 m² + 6.28 m²
= 30.28 m²
Area of the figure = 30.28 m²
So here is what you would do:
lets just pretend that there is no x in the equation
so this is what the equation would look like:
first, is 4 to the power of 2=16 and now we are going to put the x back into the equation so: 4x to the power of 2, but we did the exponents so, now x is the missing number. We can use the 32 because it is the solution to the equation. So we would do 32-16=16 so the missing number is 16 so x=16
Answer: x=16
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus
First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.
Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.
For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.



Similarly, we have



Now, to find the lengths of the diagonals,


So, the lengths of the diagonals are 10 and 10√3.
Answer: 10 and 10√3 units
The angle passes 90 degrees plus an additional 55 degrees
m