Question

Charlie has a piece of toast that has cream cheese on one side, and he dropped it once. One time, it landed with the cream cheese side up. If he drops it 2 more times, what is the probability that it will have landed cream cheese side up a total of 3 times? (1 point)

Answer 1

Answer:

Probability of landing  cream cheese side up 3 times is tex]\frac{1}{4}[/tex]

Step-by-step explanation:

The probability of getting cheese side up is one half ($\frac{1}{2}$.

And this probability does not depend on the result of the last time you dropped it or the result before that.

So every time you drop a piece of toast the probability of getting cheese side up is one half ($\frac{1}{2}$.

Charlie has already dropped it once (1st time) and it landed on cream cheese side up. So probability for this is 1 because it has already happened.

Next time (2nd time) he drops, the probability of landing cream cheese side up is $\frac{1}{2}$

When he drops the piece of toast again (3rd time) the probability of landing cheese side up is again $\frac{1}{2}$.

So the probability of landing  cream cheese side up 3 times is,

$1*\frac{1}{2} *\frac{1}{2}$

=$\frac{1}{4}$

Answer 2

Answer:

The answer is 1/4 or A