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a_sh-v [17]
2 years ago
12

A small square at the right corner of the table is what?​

Computers and Technology
1 answer:
Triss [41]2 years ago
8 0
Ask your dad what you your name
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Jason works as an accountant in a department store. He needs to keep a daily record of all the invoices issued by the store. Whi
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1.) what is the minimum number of bits required to represent -3,997 using 2's complement form?
lisabon 2012 [21]

The binary representation of +3997 is 1111 1001 1101.

In one's complement this is simply adding a sign bit and inverting all the bits:

1 0000 0110 0010

The two's complement is the one's complement plus 1:

1 0000 0110 0011

That's 13 bits. Normally the sign bit would be at an 8, 16 or 32,... bit boundary.

For -436 it's 10 0100 1100 and 10 bits


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3 years ago
The spreadsheet below shows a list of fruits with their calorie count, grams of sugar, dietary fiber, and protein. Which set of
dangina [55]

Answer:

Filter Calories by over 100 calories, and sort Sugar in descending order.

Explanation:

4 0
2 years ago
The open items on your computer are displayed here.
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The GUI or Graphical <u /><u></u><em />User Interface.
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2 years ago
The following checksum formula is widely used by banks and credit card companies to validate legal account numbers: d0 + f(d1) +
Aleksandr [31]

Answer:

Here is the JAVA program:

import java.util.Scanner; //to import Scanner class

public class ISBN

{   public static void main(String[] args)  { // start of main() function body

   Scanner s = new Scanner(System.in); // creates Scanner object

//prompts the user to enter 10 digit integer

   System.out.println("Enter the digits of an ISBN as integer: ");    

   String number = s.next(); // reads the number from the user

   int sum = 0; // stores the sum of the digits

   for (int i = 2; i <= number.length(); i++) {

//loop starts and continues till the end of the number is reached by i

          sum += (i * number.charAt(i - 1) ); }

/*this statement multiplies each digit of the number with i and adds the value of sum to the product result and stores in the sum variable*/

          int remainder = (sum % 11);  // take mod of sum by 11 to get checksum  

   if (remainder == 10)

/*if remainder is equal to 10 adds X at the end of given isbn number as checksum value */

  { System.out.println("The ISBN number is " + number + "X"); }

  else

// displays input number with the checksum value computed

 {System.out.println("The ISBN number is " + number + remainder); }  }  }  

Explanation:

This program takes a 10-digit integer as a command line argument and uses Scanner class to accept input from the user.

The for loop has a variable i that starts from 2 and the loop terminates when the value of i exceeds 10 and this loop multiplies each digit of the input number with the i and this product is added and stored in variable sum. charAt() function is used to return a char value at i-1.

This is done in the following way: suppose d represents each digit:

sum=d1 * 1 + d2 * 2 + d3 * 3 + d4 * 4 + d5 * 5 + d6 * 6 + d7 * 7 + d8 * 8 + d9 * 9

Next the mod operator is used to get the remainder by dividing the value of sum with 11 in order to find the checksum and stores the result in remainder variable.

If the value of remainder is equal to 10 then use X for 10 and the output will be the 10 digits and the 11th digit checksum (last digit) is X.

If the value of remainder is not equal to 10, then it prints a valid 11-digit number with the given integer as its first 10 digits and the checksum computed by sum % 11 as the last digit.  

8 0
2 years ago
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