Answer: AWS CodeCommit
Explanation:
The AWS service that the developers can use to meet the requirements that are illustrated in the question is the AWS CodeCommit.
The AWS CodeCommit is refered to as a fully-managed source control service which can be used in the hosting of Git-based repositories which are secure.
AWS CodeCommit makes it easy for the collaboration on code for teams in a secure ecosystem. CodeCommit can securely store binaries, source code etc.
I believe the answer would be the JPEG file extension.
Answer:
list1 = [1, 2, 3]
list2 = [4, 5, 6]
list3 = []
newlist = []
for i in list1:
for j in list2:
if list1.index(i) == list2.index(j):
newlist.append(j)
newlist.append(i)
break
for i in reversed(newlist):
list3.append(i)
print(list3)
Explanation:
The programming language used is python.
List 1 and 2 are initialized, and two empty lists are initialized too, these two lists are going to be used in generating the new list.
Two FOR loops are used for both list one and two respectively, to iterate through their content, the IF statement and the break is placed within the for loop to ensure that there is no repetition.
The index of list 1 and list 2 are appended (added) to a new list one at a time.
The new list is then reversed and its content are added to list 3 to give the final solution.
NOTE: The reason a separate list was created was because the reversed() function does not return a list, so in order to get the list, it must be added to an empty list as you reverse it.
Answer:
The solution code is written in Python 3
- def findStr(stringList, c):
- output = []
- for currentStr in stringList:
- if c not in currentStr.lower():
- output.append(currentStr)
- return output
-
- strList = ["Apple", "Banana", "Grape", "Orange", "Watermelon"]
- print(findStr(strList, "g"))
Explanation:
Firstly, we can create a function and name it as findStr which takes two input parameters stringList and a character, c (Line 1).
Create a list that will hold the list of strings that do not contain the input character (Line 2).
Create a for-loop to traverse through each string in the list (Line 3).
In the loop, check if the input character is not found in the current string (Line 4), if so, add the current string to the output list (Line 5). Please note we also need to convert the current string to lowercase as this program should ignore the casing.
After completion the loop, return the output list (Line 7).
We can test the function using a sample string list and input character "g" (Line 9 - 10). We shall get the output as follows:
['Apple', 'Banana', 'Watermelon']
