It proceeds the statement causes execution of the current loop iteration to end and commence at the beginning of the next loop.

Aye yo, how do I get rid of an already placed end crystal? I thought it looked cool to build in my minecraft survival house, and

SpyIntel [72]

Answer:

they can be removed safely if they're immersed in water first.

Explanation:

8 0

4 years ago

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Place the following discoverers in the correct chronological order of the timeframe for their discoveries, from earliest to most

Alex787 [66]

The correct order or answer is the 2nd choice.

Pythagoras, Gauss, Edison, Hawking. The following are the most noted discoveries of each.

Pythagoras, 500 B.C. School Of Mathematics and Pythagorean theorem.Edison, Year 1879 - Invention of incandescent light bulb.Gauss, Year 1801 - Therom of Alegbraic Solution. Stephen Hawking Year1980 - Studies in cosmology particularly contributing to the context of black holes.

5 0

3 years ago

A technician wants to configure the inbound port of a router to prevent FTP traffic from leaving the LAN.

Archy [21]

Answer:

The technician will want to add ACL for ports 20 and 21

Explanation:

The FTP protocol by default will attempt to use 21 for TCP access and 20 for data access. By enabling an Access Control List (ACL) on ports 20 and 21, the technician can prevent FTP traffic from leaving the network on the default ports.

Cheers.

8 0

3 years ago

Suppose that instead of swapping element A[i] with a random element from the subarray A[i..n], we swapped it with a random eleme

Anastaziya [24]

Answer:

The answer to this question can be defined as follows:

Explanation:

Its Permute-with-all method, which doesn't result in a consistent randomized permutation. It takes into account this same permutation, which occurs while n=3. There's many 3 of each other, when the random calls, with each one of three different values returned and so, the value is= 27. Allow-with-all trying to call possible outcomes as of 3! = 6

Permutations, when a random initial permutation has been made, there will now be any possible combination 1/6 times, that is an integer number m times, where each permutation will have to occur m/27= 1/6. this condition is not fulfilled by the Integer m.

Yes, if you've got the permutation of < 1,2,3 > as well as how to find out design, in which often get the following with permute-with-all chances, which can be defined as follows:

$\bold{PERMUTATION \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ PROBABILITY}$

$\bold{ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4/27= 0.14 }\\\bold{ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5/27=0.18}\\$

$\bold{ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5/27=0.18}\\\bold{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5/27=0.18}$

$\bold{ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4/27=0.14}$

Although these ADD to 1 none are equal to 1/6.

7 0

3 years ago

Hey guy its hailey and my favorite song is the start of somethin new

miss Akunina [59]

Lol that’s cool..........

8 0

3 years ago

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