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murzikaleks [220]
2 years ago
7

At the city museum, child admission is $6.20 and adult admission is $9.40. On Thursday, 163 tickets were sold for a total sales

of $1221.80. How many adult
tickets were sold that day?
Mathematics
1 answer:
Tju [1.3M]2 years ago
4 0
<h2>Systems of Equations</h2>

To form a system of equation from a word problem, we must recognize different variables to form different equations.

<h2>Solving the Question</h2>

Let <em>a</em> represent the number of child tickets.

Let <em>b</em> represent the number of adult tickets.

We're given:

  • 1a = $6.20
  • 1b = $9.40
  • a and b in total is 163
  • Total sales = $1221.80

Because we're given that a and b in total is 163, we can form the following equation:

a+b=163

We're also given that the total sales made is $1221.80. Because we know that 1a = $6.20 and 1b = $9.40, we can also form the following equation:

6.2a+9.4b=1221.8

Here are our two equations:

a+b=163

6.2a+9.4b=1221.8

<h3>Solving the System of Equations</h3>

We can solve using the method of elimination. Multiply both sides by 6.2 in the first equation:

6.2(a+b)=6.2(163)\\6.2a+6.2b=1010.6

Subtract this new equation from the second equation to cancel out <em>a</em>:

\hspace{10}6.2a+9.4b=1221.8\\- 6.2a+6.2b=1010.6\\\rule{100}{0.5}\\3.2b=211.2

Solve for <em>b</em>:

b=66

Therefore, the number of adult tickets sold is 66.

<h2>Answer</h2>

66

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------------------------

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The expression is:

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