Original price of the item = $14.95
Price after discount = $13.79
Discount offered = original price - price after discount = 14.95- 13.79 = $1.16
Now let us find the percentage of discount offered.
Percentage discount is given by the formula:

Where MP= Marked price= original price
SP= selling price= price after discount

Percentage discount = 7.759 %
Step-by-step explanation:
option C
hope it helps
thank you
The trick is to exploit the difference of squares formula,

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

Whatever you do to the denominator, you have to do to the numerator too. So

Expand the numerator:






So we have

But √12 = √(3•4) = 2√3, so

Answer:
36 people
Step-by-step explanation:
If the yearbook club had 1/2 the participants attend the meeting, than all of them would be represented by 18 x 2, or 36 (since two halves make a whole)