All categories

2 years ago

A recipe for dessert calls for 1/3 cup of powdered sugar and 2/6 cup of brown

Mathematics

1 answer:

Gemiola [76]2 years ago

6 0

Answer:

2/3

Step-by-step explanation:

1/3 cup powdered sugar

2/6 cup brown sugar

Reduce 2/6 to 1/3.

1/3 + 1/3 = 2/3

You might be interested in

How can i figure out this problem it is 3/6+10/12

Viktor [21]

3/6 + 10/12 to finish this math problem you just need to simplify 3/6 with the number 2 the number up and down like this
3*2/6*2 +10/12 = 6/12 +10/12 =16/12
And you have finished! Hope I helped

8 0

3 years ago

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

3 years ago

P = {x:x is a multiple of 4, x ≤ 20} and Q = (x:x is a multiple of 5, x ≤ 20 }

ioda

Answer:

Hope it will help you.....

Step-by-step explanation:

my answer is

P=(4,8,12,16,20)

Q=(5,10,15,20)

5 0

3 years ago

Which of the following lines is parallel to line y=-1/2x-6

Tasya [4]

Whichever line has the same slope (-1/2) as this line is the answer

5 0

3 years ago

For f(x) = 2x + 1 and g(x) = x^2- 7, find (f - g)(x). ?

Irina18 [472]

Answer:

(f-g)(x)=-x^(2)+2x+8

the solutions are:

x=4 or x=-2

Step-by-step explanation:

(f-g)(x)=2x+1-(x^(2)-7)

(f-g)(x)=-x^(2)+2x+1+7

(f-g)(x)=-x^(2)+2x+8

does this help or should I solve for the zeros/solutions of this quadratic equation?

then:

-x^(2)+2x+8=0

-(x^(2)-2x-8)=0

x^(2)-2x-8=0

(x-4)(x+2)=0

x=4 or x=-2

4 0

3 years ago

Read 2 more answers