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Artyom0805 [142]
3 years ago
12

P = {x:x is a multiple of 4, x ≤ 20} and Q = (x:x is a multiple of 5, x ≤ 20 } ​

Mathematics
1 answer:
ioda3 years ago
5 0

Answer:

Hope it will help you.....

Step-by-step explanation:

my answer is

P=(4,8,12,16,20)

Q=(5,10,15,20)

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c = -8

Step-by-step explanation:

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irinina [24]

Answer:

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Step-by-step explanation:

30/8=3.75 mi in one hour

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2 years ago
A) 3y = 43 + x<br><br> b) 8y + 5x = 61
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Answer:

huh

Step-by-step explanation:

7 0
2 years ago
The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second. Use the central limi
Mila [183]

Answer:

0.048 is the probability that more than 950 message arrive in one minute.

Step-by-step explanation:

We are given the following information in the question:

The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.

Let X be the number of messages arriving at a multiplexer.

Mean = 15

For poison distribution,

Mean = Variance = 15

\text{Standard Deviation} = \sqrt{\text{Variance}} = \sqrt{15} = 3.872

From central limit theorem, we have:

z = \displaystyle\frac{x-n\mu}{\sigma\sqrt{n}}

where n is the sample size.

Here, n = 1 minute = 60 seconds

P(x > 950)

P( x > 950) = P( z > \displaystyle\frac{950 - (60)(15)}{\sqrt{(15)(60)}}) = P(z > 1.667)

= 1 - P(z \leq 1.667)

Calculation the value from standard normal z table, we have,  

P(x > 950) = 1 - 0.952 = 0.048

0.048 is the probability that more than 950 message arrive in one minute.

3 0
3 years ago
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