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2 years ago

(7)/(3) of it is 5 (5)/(6)

1 answer:

7 0

let's firstly convert the mixed fraction to improper fraction and then take it from there, keeping in mind that the whole is "x".

$\stackrel{mixed}{5\frac{5}{6}}\implies \cfrac{5\cdot 6+5}{6}\implies \stackrel{improper}{\cfrac{35}{6}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{7}{3}x~~ = ~~5\frac{5}{6}\implies \cfrac{7}{3}x~~ = ~~\cfrac{35}{6}\implies 42x=105\implies x=\cfrac{105}{42} \\\\\\ x=\cfrac{21\cdot 5}{21\cdot 2}\implies x=\cfrac{21}{21}\cdot \cfrac{5}{2}\implies x=1\cdot \cfrac{5}{2}\implies x=2\frac{1}{2}$

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The formula Upper A equals 23.1 e Superscript 0.0152 tA=23.1e0.0152t models the population of a US state, A, in millions, t ye

Wewaii [24]

Answer:

a) $A(t=0)= 23.1 e^{0.0152(0)}=23.1e^0 =23.1$

b) $t = \frac{ln(\frac{28.3}{23.1})}{0.0152}=13.357 years$

So for this case the answer would be 13.347 years, the population will be 28.3 million and ye year would be 2000+13.347 and that would be approximately in 2014

Step-by-step explanation:

For this case we assume the following model:

$A(t)= 23.1 e^{0.0152 t}$

Where t is the number of years after 2000/

Part a

For this case we want the population for 2000 and on this case the value of t=0 since we have 0 years after 2000. If we rpelace into the model we got:

$A(t=0)= 23.1 e^{0.0152(0)}=23.1e^0 =23.1$

So then the initial population at year 2000 is 23.1 million of people.

Part b

For this case we want to find the time t whn the population is 28.3 million.

So we need to solve this equation:

$28.3= 23.1 e^{0.0152(t)}$

We can divide both sides by 23.1 and we got:

$\frac{28.3}{23.1}= e^{0.0152t}$

Now we can apply natural log on both sides and we got:

$ln(\frac{28.3}{23.1})= 0.0152 t$

And then for t we got:

$t = \frac{ln(\frac{28.3}{23.1})}{0.0152}=13.357 years$

So for this case the answer would be 13.347 years, the population will be 28.3 million and ye year would be 2000+13.347 and that would be approximately in 2014

3 0

3 years ago

Please help me with these

Margaret [11]

= 3^3 - |-39 | / (-3)
= 27 - (-13)
= 40

9)
top:
3(2)^3 / 6 +(-5)
= 24/6 - 5
= 4 - 5
= -1

bottom:
= 5 - 4 - 27/9 *3
= 5 - 4 - 3*3
= 5 -4 - 9
= -8
so
-1 / -8 = 1/8

answer
1/8

8 0

3 years ago

A company is approached by a new warehouse management systems vendor to adopt a new system. The vendor claims that the warehouse

Ludmilka [50]

Answer:

The null hypothesis is $H_o : \mu = 180$

The alternative hypothesis is $H_a : \mu < 180$

The decision rule is fail to reject the null hypothesis

The conclusion

There no sufficient evidence to support the vendor claim that the warehouse management system reduces the average pick, pack, and ship time to below 3 minutes(180 seconds) per order through bin location and routing optimization

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 3 \ minutes = 180 \ seconds$