Answer:
After 3 seconds while going up and 6 seconds while coming down
Step-by-step explanation:
Since projectile is launched from ground level with an initial velocity of v 0 feet per second, initial height =0
Height is given by
where v0 = initial velocity = 144
a) When h =288 ft.
At t= 3 or 6 seconds the projectile would be at height 288 ft.
So while going up after 3 seconds it wouldbe at a height of 288 ft and while coming after 6 seconds.
Use the distributive property to multiply -3 by 3m+7.
Combine 19m and -9m to get 10m.
Subtract 21 from -14 to get -35.
Answer:
OPTION D
Step-by-step explanation:
We have to determine which option determines the function given above.
To determine the function, just substitute the values and compare LHS and RHS.
we have
Here, is the domain and
is the co-doamin.
Therefore,
Now, OPTION A:
Substitute x = 4. We get f(x) = 3 18.
So, OPTION A is rejected.
Similarly, OPTION B:
Substitute x = 4. We get f(4) = 22 18.
It is rejected as well.
Now, for OPTION C:
Substitute x = 4. We get f(4) = -3 18.
So, OPTION C is also rejected.
OPTION D:
Substitute x = 4. We get f(4) = 18.
Substitute the remaining points in domain as well. We notice that it exactly matches the given function. So, OPTION D is the answer.