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garri49 [273]
2 years ago
11

Has a base of 3, is reflected over the y-axis, has a horizontal shift right by 5 and an asymptote of y=-3

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
3 0

The equation of the exponential function is y = 3^{-x -5} - 3

<h3>How to determine the equation?</h3>

An exponential equation is represented as:

y = b^x

Where b represents the base.

The base is 3.

So, we have:

y = 3^x

When reflected over the y-axis, we have:

y = 3^{-x

When shifted right by 5 units, we have:

y = 3^{-x -5

Lastly, the function has an asymptote of y=-3

So, we have:

y = 3^{-x -5} - 3

Hence, the equation of the exponential function is y = 3^{-x -5} - 3

Read more about exponential function at

brainly.com/question/2456547

#SPJ1

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gayaneshka [121]

Answer:

y=-15x+b

Step-by-step explanation:

Just move it around and use a calucator

8 0
3 years ago
What does 90-3x equal
Nikolay [14]
90-3x=?

Get x to one side 

So minus 90 from each side

-3x=-90

-90÷-3=30

Answer: x=30 

6 0
3 years ago
I need help!!! Please help me cuties<br> REPORTING LINKS!!
vitfil [10]

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1. 15.4

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3. 13.16

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Step-by-step explanation:

7 0
3 years ago
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Using the Quadratic Formula, which of the following is the solution to the quadratic equation x2 + 2x - 3 = 0?
saw5 [17]

Answer: x=1 or x=-3

Step-by-step explanation:

Quadratic formula is -b+-\sqrt{b^{2}-4ac } /2

a=1 b=2 c=-3

Substitute

(-2+-\sqrt{2^{2}-4(1)(-3) }) /2\\(-2+-\sqrt{4+12}) /12\\(-2+-\sqrt{16}) /2\\(-2+-4) /2\\x=\frac{-2+4}{2} \\x=\frac{-2-4}{2} \\\\\\Simplify\\x=\frac{2}{2} \\\\x=\frac{-6}{2} \\\\Simplify\\x=1\\x=-3

6 0
4 years ago
#10<br> Write the equation of the given circle.<br><br> center (-2, -2)<br> radius of 6
Roman55 [17]
(x - h)^2 + (y - k)^2 = r^2

h = -2
k = -2
r = 6

(x - (-2))^2 + (y - (-2))^2 = 6^2

(x + 2)^2 + (y + 2)^2 = 6^2

(x + 2)^2 + (y + 2)^2 = 36. your answer

hope this helped, blessings! :)
6 0
3 years ago
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