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3 years ago

Negative square root negative 48

1 answer:

6 0

6.928203230275509 is the exact answer but if you wanna round it to the nearest tenth its 6.9 and the nearest hundredth is 6.95

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An ordinary single die is thrown. Find the probability that an even number is the outcome.

Nikolay [14]

You will have a 3:6 probability of getting an even number

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3 years ago

How can you determine if two expressions are equivalent?

Vladimir [108]

Simplify them until they can be simplified no more, then compare both sides.

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3 years ago

Most dietitians recommend that adults consume 20 to 30 percent of their daily caloric intake in protein. Based on this recommend

labwork [276]

Answer:

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3 years ago

A cargo grain leaves Chicago at noon travelling west at 120 km/h. At 2 pm, a passenger train leaves Chicago travelling east at 3

AfilCa [17]

Answer:

a) The trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) At that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

Step-by-step explanation:

a) First, we need to find the distance traveled by the cargo train in the two hours before the passenger train leaves Chicago:

$x_{1} = v_{1}t_{1} = 120 km/h*2h = 240 km$

Now, we can find the time when the trains will be 1520 km apart:

$1520 km = (x_{1} + 240 km) + x_{2}$

Where 1 is for the cargo train and 2 is for the passenger train.

$1520 km = (v_{1}*t_{1} + 240 km) + v_{2}t_{2}$

Since we need to calculate the time when the trains are 1520 km apart, t₁ = t₂, so:

$1520 km = (v_{1}*t + 240 km) + v_{2}t$

$t = \frac{1520 km - 240 km}{120 km/h + 360 km/h} = 2.667h$

For the cargo train, it will be 1520 km apart from the passenger train at:

$t_{1} = 12 pm + 2 h + 40 min = 2:40 pm$

And for a passenger train, it will be 1520 km apart from the cargo train at:

$t_{2} = 2 pm + 2 h + 40 min = 4:40 pm$

Hence, the trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) The distance traveled by both trains is given by:

$x_{1} = v_{1}*t + 240 km = 120 km/h*2.667 h + 240 km = 560.04 km$

$x_{2} = v_{2}*t = 360 km/h*2.667 h = 960.12 km$

Therefore, at that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

I hope it helps you!

5 0

2 years ago

HELP ASAP ILL GIVE BRAINLIST

Mila [183]

Answer:

Part A) ΔCGB and ΔPBE are similiar

Part B) They are similar because they are Vertical Angles/Alternate Interior Angles

Part C) Distance from B to E is 125; Distance from P to E is 275.

Step-by-step explanation:

5 0

2 years ago