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Bas_tet [7]
2 years ago
5

Without exponents logc (xy^6z^-4) what is the equivalent expression

Mathematics
1 answer:
Sever21 [200]2 years ago
5 0

By eliminating exponents, the <em>logarithmic</em> expression \log_{c} x\cdot y^{6}\cdot z^{-4} is equivalent to the <em>logarithmic</em> expression \log_{c} x + 6\cdot \log_{c} y - 4\cdot \log_{c} z.

<h3>How to simplify logarithmic functions</h3>

In this problem we are supposed to eliminate all exponents of a <em>logarithmic</em> function by applying any of the following properties:

  1. ㏒ x · y = ㏒ x + ㏒ y
  2. ㏒ x/y = ㏒ x - ㏒ y
  3. ㏒ yˣ = x · ㏒ y

Now, we proceed to simplify the function:

\log_{c} x\cdot y^{6}\cdot z^{-4}

\log_{c} x + \log_{c} y^{6} + \log_{c} z^{-4}

\log_{c} x + 6\cdot \log_{c} y - 4\cdot \log_{c} z

By eliminating exponents, the <em>logarithmic</em> expression \log_{c} x\cdot y^{6}\cdot z^{-4} is equivalent to the <em>logarithmic</em> expression \log_{c} x + 6\cdot \log_{c} y - 4\cdot \log_{c} z.

To learn more on logarithms: brainly.com/question/24211708

#SPJ1

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