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kumpel [21]
3 years ago
8

The ratio of the number of Mays necklaces to the number of Helen's necklace is 25:9. May has 100 necklaces. How many necklaces d

oes Helen have.
Mathematics
1 answer:
likoan [24]3 years ago
6 0

Answer:

36

Step-by-step explanation:

25:9

25*4 = 100

9*4 = 36

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She has 38 balloons altogether
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Can someone help me figure out the answer , this stuff is hard .
DedPeter [7]
How do you upload the pictures on here?
7 0
3 years ago
Can someone solve and explain it to me please
lys-0071 [83]

Answer is C) 6

36 + 3(4x - 9) = 6(2x + 1)

36 + 12x - 27 = 12x + 6

12x - 12x = 6 - 9

0 ≠ -3

No solution

3 0
3 years ago
What is the simplified form of
umka21 [38]

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

Answer:

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4

Step-by-step explanation:

Given the expression

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)

solving the expression

=-7x^0+5x^2-x+6-\left(-8x^2+x+3\right)

apply the rule: a^0=1,\:a\ne \:0

=-7+5x^2-x+6-\left(-8x^2+x+3\right)

=-7+5x^2-x+6+8x^2-x-3

simplify

=13x^2-2x-4

Therefore, the simplified form is:

\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

8 0
3 years ago
Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the ai
ss7ja [257]

Answer:

The probability that the plane is oveloaded is P=0.9983.

The pilot should take out the baggage and send it in another plain or have less passengers in the plain to not overload.

Step-by-step explanation:

The aircraft will be overloaded if the mean weight of the passengers is greater than 163 lb.

If the plane is full, we have 41 men in the plane. This is our sample size.

The weights of men are normally distributed with a mean of 180.5 lb and a standard deviation of 38.2.

So the mean of the sample is 180.5 lb (equal to the population mean).

The standard deviation is:

\sigma=\frac{\sigma}{\sqrt{N}} =\frac{38.2}{\sqrt{41}}=\frac{38.2}{6.4} =5.97

Then, we can calculate the z value for x=163 lb.

z=\frac{x-\mu}{\sigma}=\frac{163-180.5}{5.97}=\frac{-17.5}{5.97}=   -2.93

The probability that the mean weight of the men in the airplane is below 163 lb is P=0.0017

P(\bar X

Then the probability that the plane is oveloaded is P=0.9983:

P(overloaded)=1-P(X

The pilot should take out the baggage or have less passengers in the plain to not overload.

7 0
3 years ago
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