Answer:
Option 2 is correct.
Step-by-step explanation:
Given the coordinates of lines segment (3, 10) and (7, 8). we have to find the mid-point of given line segment.
Mid-point formula states that if 
and 
are the coordinates of end points of line segment then the coordinates of mid-point are
∴ Coordinates of mid-point of line segment joining the points (3, 10) and (7, 8) are
Hence, option 2 is correct.
If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
___________________________________________
If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
Answer:
<u>x = -3</u>
Step-by-step explanation:
-5x + 9 = 24
move the nine to the other side
-5x = 15
divide
x = -3
