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1 year ago

Find the discriminant of the following quadratic equation x^-5x+3=0

1 answer:

8 0

The discriminant of the given quadratic equation as in the task content can be evaluated by means of the formula; D = b²-4ac and it's value is; 13.

<h3>What is the discriminant of the quadratic equation as given in the task content?</h3>

According to the task content, it follows that the quadratic equation whose discriminant is to be determined is; x²-5x+3=0.

By comparison with the standard form equation of a quadratic graph which goes thus; ax²+bx +c = 0, in which case, the determinant is given by the expression; b² - 4ac.

We can consequently evaluate the determinant of the quadratic equation in discuss as follows;

Determinant = b² -4ac = (-5)² - (4×1×3) = 25 - 12

Hence, the determinant in this case is; 13.

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If f(x) = 3x + 10 and g(x) = 2x - 4, find (f+ g)(x).

ad-work [718]

Answer:

5x+6

Step-by-step explanation:

f(x) = 3x + 10

g(x) = 2x - 4

(f+ g)(x)= 3x + 10 + 2x - 4

Combine like terms

= 5x+6

7 0

3 years ago

6 students share 4 bagels equally. How many pieces does each person get? (p.s thanks to everyone who answers)

bija089 [108]

Hi!

You would get 1 and a half bagel for each person

6/4 = 1 1/2 or 1.5

5 0

3 years ago

Read 2 more answers

Given that

zloy xaker [14]

g(x) = f(x) + 9 shifts it up 9 units.

g(x) = f(x+2) shifts it left 2 units.

g(x) = -f(x) reflects it across the x-axis.

It looks like you may want

... g(x) = -(f(x+2) +9) . . . . . shifted up, then reflected

$g(x)=-\left(5^{(x+2)}+9\right)$

4 0

3 years ago

Find the value or x. - a. 5 b. 11 c. 25 d. 31

zhenek [66]

11 because it is bigger than EB and smaller then DF

4 0

2 years ago

Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio, si avanza medio kilómetro en bus y lo demás a pie ¿

Murljashka [212]

Answer:

Al estudiante le falta caminar $\frac{1}{3}$ de kilómetro.

Step-by-step explanation:

Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio. Dos tercios equivale a la fracción $\frac{2}{3}$ .

El estudiante avanza medio kilómetro en bus. Un medio equivale a la fracción $\frac{1}{2}$ , por lo tanto un medio es la mitad de una cantidad. Para calcular la distancia recorrida en bus se realiza la siguiente multiplicación:

$\frac{1}{2} *\frac{2}{3}$

Resolviendo:

$\frac{1}{2} *\frac{2}{3} =\frac{1*2}{2*3} =\frac{2}{6} =\frac{1}{3}$

Entonces, la distancia recorrida en bus es $\frac{1}{3}$ de kilómetro.

Para calcular la distancia recorrida a pie se calcula la diferencia entre la distancia total a recorrer por el estudiante y la distancia recorrida en bus. Esto es:

$\frac{2}{3} - \frac{1}{3}$

Resolviendo:

$\frac{2}{3} - \frac{1}{3}=\frac{2-1}{3} =\frac{1}{3}$

Al estudiante le falta caminar $\frac{1}{3}$ de kilómetro.

6 0

3 years ago