Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
0 + (-3 1/4)
1 + (-4 1/4)
2 + (-5 1/4)
The correct answer is: [C]: " c(x) = –8x²<span> + 3x – 5 " .
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The quadratic function takes the form of:
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" f(x) = ax</span>² + bx + c " .
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Answer choice: [C]: " c(x) = –8x² + 3x – 5 " ;
is the only answer choice provided that takes that form of the quadratic function:
" f(x) = ax² + bx + c " :
in which: " a = -8 " ; " b = 3 " ; " c = -5 " .
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So 7 is greater I am not smart I am just trying to answers some question
That would be 6 *3 - 8*0 = 18
Its D