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enot [183]
2 years ago
9

PLLLLLEASE T_T PLLLEASE

Mathematics
1 answer:
maxonik [38]2 years ago
4 0

{\qquad\qquad\huge\underline{{\sf Answer}}}

let's solve ~

\qquad \sf  \dashrightarrow \:  \cfrac{4}{y - 6} +  \cfrac{5}{y + 3}   =  \cfrac{7y - 4}{ {y}^{2}  - 3y - 18}

\qquad \sf  \dashrightarrow \:  \cfrac{4(y + 3) + 5(y - 6)}{(y - 6)(y + 3)}  =  \cfrac{7y - 4}{ {y}^{2}  - 3y - 18}

\qquad \sf  \dashrightarrow \:  \cfrac{4y + 12 + 5y - 30}{ {y}^{2}  +  3y - 6y - 18 }  =  \cfrac{7y - 4}{ {y}^{2}  - 3y - 18}

\qquad \sf  \dashrightarrow \:  \cfrac{9y  - 18}{ {y}^{2}   - 3y - 18 }  =  \cfrac{7y - 4}{ {y}^{2}  - 3y - 18}

\qquad \sf  \dashrightarrow \: 9y - 18 = 7y - 4

[ denominator is same, so numerator must have same value to be equal ]

\qquad \sf  \dashrightarrow \: 9y - 7y =   - 4 + 18

\qquad \sf  \dashrightarrow \: 2y = 14

\qquad \sf  \dashrightarrow \: y = 7

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