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2 years ago

PLLLLLEASE T_T PLLLEASE

Mathematics

1 answer:

maxonik [38]2 years ago

4 0

${\qquad\qquad\huge\underline{{\sf Answer}}}$

let's solve ~

$\qquad \sf \dashrightarrow \: \cfrac{4}{y - 6} + \cfrac{5}{y + 3} = \cfrac{7y - 4}{ {y}^{2} - 3y - 18}$

$\qquad \sf \dashrightarrow \: \cfrac{4(y + 3) + 5(y - 6)}{(y - 6)(y + 3)} = \cfrac{7y - 4}{ {y}^{2} - 3y - 18}$

$\qquad \sf \dashrightarrow \: \cfrac{4y + 12 + 5y - 30}{ {y}^{2} + 3y - 6y - 18 } = \cfrac{7y - 4}{ {y}^{2} - 3y - 18}$

$\qquad \sf \dashrightarrow \: \cfrac{9y - 18}{ {y}^{2} - 3y - 18 } = \cfrac{7y - 4}{ {y}^{2} - 3y - 18}$

$\qquad \sf \dashrightarrow \: 9y - 18 = 7y - 4$

[ denominator is same, so numerator must have same value to be equal ]

$\qquad \sf \dashrightarrow \: 9y - 7y = - 4 + 18$

$\qquad \sf \dashrightarrow \: 2y = 14$

$\qquad \sf \dashrightarrow \: y = 7$

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A very large book is numbered to 1 to 11521 How many digits are used to print all these page numbers

stealth61 [152]

Answer:

46,499 digits

Step-by-step explanation:

Total pages of book = 11,521

9 pages numbered 1 - 9 that need 1 digit each = 9 × 1

= 9 digits

90 pages numbered 10 - 99 that need 2 digits each = 90 × 2

= 180 digits

900 pages numbered 100 - 999 that need 3 digits each = 900 × 3

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9000 pages numbered 1000 - 9999 that need 4 digits each = 9000 × 4

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1522 pages numbered 1000 - 11521 that need 5 digits each = 1522 × 5

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Total digits needed = 9 digits + 180 digits + 2,700 digits + 36,000 digits + 7,610 digits

= 46,499 digits

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3 years ago

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tester [92]

Answer:

$\%Percent = 17.14\%$

Step-by-step explanation:

Given

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$Protein = 60\ g$

$Fat = 40\ g$

Required

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First, we need to calculate the total:

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Percentage of protein is calculated as thus:

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3 years ago

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3 years ago

According to the Census Bureau, 3.39 people reside in the typical American household. A sample of 26 households in Arizona retir

Vikki [24]

Answer:

$t=\frac{2.73-3.39}{\frac{1.22}{\sqrt{26}}}=-2.758$

$df=n-1=26-1=25$

$p_v =P(t_{(25)}$

Since the p value is lower than the significance level 0.1 we have enough evidence to reject the null hypothesis, and we can conclude that the true mean is significanlty lower than 3.39 personas at 10% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=2.73$ represent the sample mean

$s=1.22$ represent the sample standard deviation

$n=26$ sample size

$\mu_o =3.39$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is less than 3.39 persons, the system of hypothesis would be:

Null hypothesis: $\mu \geq 3.39$

Alternative hypothesis: $\mu < 3.39$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.73-3.39}{\frac{1.22}{\sqrt{26}}}=-2.758$

P-value

The degreed of freedom are given by:

$df=n-1=26-1=25$

Since is a one sided lower test the p value would be:

$p_v =P(t_{(25)}$

Conclusion

3 0

2 years ago