I cant really show you how to graph this but i can try to explain it. you would make a 4 quadrant graph and do rise over run.
1)start by making the graph
2) on the line of the graph marked Y is where you would put -4
3) From -4, you would go up (rise) by 2 and go over to the right 1 where you end is the slop
If triangle ABC is congruent to triangle DEF, then EF = BC = 27
This is because BC and EF are the last two letters of ABC and DEF respectively. They match up and correspond, being congruent by CPCTC
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Similarly, if triangle ABC is congruent to triangle DEF, then angle D = angle A = 49 degrees
The letter D and the letter A are the first letters of DEF and ABC respectively. So they match up and are congruent by CPCTC
CPCTC = Corresponding Parts of Congruent Triangles are Congruent
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So in short, the answer is choice B) 27; 49
Answer:
B
Step-by-step explanation:
Rewriting in slope-intercept form.
x - 2y = 0
Add -x on both sides.
- 2y = 0 - x
Divide both sides by -2.
y = 0/-2 - x/-2
y = 0 - - 1/2x
y = 0 + 1/2x
y = 1/2x + 0
The slope is 1/2, the y-intercept is at (0, 0).
Answer:
answer is B
Step-by-step explanation:
step by step explanation
Answer:
1st and 2nd quadrants
Step-by-step explanation:
You have sine is positive since it is 4/5.
Sine is the y-coordinate.
On the coordinate plane y is positive in the 1st and 2nd quadrants.
