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poizon [28]
3 years ago
6

Which equation(s) have x = –3 as the solution? log3(2x + 15) = 2 log5(8x + 9) = 2 log4(–20x + 4) = 3 logx81 = 4

Mathematics
2 answers:
baherus [9]3 years ago
6 0

Answer:

log_3(2x+15)=2  and log_4(-20x+4)=3

Step-by-step explanation:

Plug it in and see!

log_3(2x+15)=2\\log_3(2(-3)+15)=2\\log_3(-6+15)=2\\log_3(9)=2\\\text{ This is a true equation because } 3^2=9\\\\\\log_5(8(-3)+9)=2\\log_5(-24+9)=2\\log_5(-15)=2\\\\\text{ Not true because you cannot do log of a negative number }\\\\log_4(-20(-3)+4)=3\\log_4(64)=3\\\text{ this is true because } 4^3=64\\\\\\log_x (81)=4\\log_{-3}(81)=4\\\text{ the base cannot be negative }\\\\\\\\\text{ There is only two options here} \\\\log_3(2x+15)=2 \text{ and } log_4(-20x+4)=3

Inessa [10]3 years ago
4 0

Answer:

A and C

Step-by-step explanation:

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<h3>Answer:</h3>

C. The playable area has a width of 9 inches and a height of 6 inches.

<h3>Explanation:</h3>

There are a number of ways you can get there.

1. Check the answers to see which have the right area and aspect ratio.

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3. You can write equations for width and height and solve.

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Substituting w=3/2·h into the second equation gives

... (3/2)h·h = 54

... h² = 36 . . . . . multiply by 2/3

... h = √36 = 6 . . . . square root, result in inches . . . . matches selection C

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