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lianna [129]
2 years ago
5

Ssignment-make sure I can open it.

Mathematics
1 answer:
bezimeni [28]2 years ago
4 0
2(2)2= 8 + 3(2)2=12 - 11(2)= 22 - 6 and 8 + 12 - 22- 6 = -8
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3x – 2y = 17 <br> –2x – 5y = 14 <br> Solve using Elimination Please show work
OleMash [197]

Answer:

The solution is x=3 , y=-4 or (3,-4)

Step-by-step explanation:

Given equations (1 and 2) are:

3x- 2y = 17\\-2x -5y = 14

To solve a system of equation with elimination method, the co-efficients of one of the variables has to be equated and then the equations are added or subtracted to get an equation in one variable.

Multiplying equation 1 by 2:

2(3x-2y) = 2*17\\6x-4y = 34\ \ \ \ \ Eqn\ 3

Multiplying equation 2 by 3

3(-2x-5y) = 3*14\\-6x-15y = 42\ \ \ \ Eqn\ 4

Adding equation 3 and 4

(6x-4y) + (-6x-15y) = 34+42\\6x-4y-6x-15y = 76\\-19y = 76\\\frac{-19y}{-19} = \frac{76}{-19}\\y = -4\\

Putting y = -4 in equation 1

3x-2(-4) = 17\\3x+8 = 17\\3x = 17-8\\3x = 9\\\frac{3x}{3} = \frac{9}{3}\\x = 3

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The solution is x=3 , y=-4 or (3,-4)

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