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Julli [10]
3 years ago
15

PLEASE HELP with these math questions (Please don't answer if you don't know all of them)

Mathematics
1 answer:
Leona [35]3 years ago
5 0
Sqrt (53) = 10 * sqrt (0.53)

0.53 = 64/121
sqrt (0.53) = sqrt (64)/ sqrt (121) = 8/11 = 0.7273
Therefore sqrt (53) = 10 * 0.7273 = 7.27

sqrt (108) = 10 * sqrt (1.08)
sqrt (1.08) = sqrt (676/625) = 26/25 = 1.04
Therefore sqrt (108) = 10 * 1.04 = 10.4

sqrt (128) = 10 * sqrt (1.28)
sqrt (1.28) = sqrt (289/225) = 17/15 = 1.133
Therefore sqrt (108) = 10 * 1.133 = 11.33

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The monthly cost of driving a car depends on the number of miles driven. Lynn found that in May her driving cost was $380 for 48
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Answer:

y=0.2x+284

Step-by-step explanation:

Let  x be the distance driven, d-distance and C our constant.

Our information can be presented as:

y=mx+c\\\\450=830x+C\ \ \ \ \ \ \ \ \ eqtn 1\\\\380=480x+C\ \ \ \ \ \ \ \ \ eqtn 2

#Subtracting equation 2 from 1:

70=350x\\x=0.2

Hence the fixed cost per mile driven,x is $0.20

To find the constant,C we substitute x in any of the equations:

450=830x+C\ \ \ \ \ \ \ X=0.2\\\therefore C=450-830\times0.2\\=284

Now, substituting our values in the linear equation:

y=0.2x+284       #y=cost of driving, x=distance driven

Hence the linear equation for the cost of driving is y+0.2x+284

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