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Soloha48 [4]
2 years ago
5

PLEASE HELP DUE TONIGHT

Mathematics
1 answer:
lukranit [14]2 years ago
6 0

The height & speed are mathematically given as

t = 0.2 s

u = 4 m/s

<h3>What is the height & speed?</h3>

Generally, the equation for height is  mathematically given as

h = 0.2gt^2

Therefore

0.2 = 0.5 * 9.8 *t^2

0.2 = 4.9 *t^2

t = 0.2 s

b)

In conclusion, the initial speed is

s = ut

Therefore

u = 0.8 / 0.2

u = 4 m/s

Read more about speed

brainly.com/question/7359669

#SPJ1

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Fiona purchased 400 m2 of plastic sheeting and needs to cut it into rectangles of area 500 cm2. This can be done with no waste.
hoa [83]

Answer:

  8000

Step-by-step explanation:

The number will be ...

  (400 m^2)/(500 cm^2) = 0.8 (m/cm)^2 = 0.8 ((100 cm)/(1 cm))^2

  = 0.8·100^2 = 8000

Fiona can cut 8000 rectangles from the plastic sheeting she bought.

5 0
3 years ago
A student simplified the expression 6^2/12^2 as 1/2 do you agree
maria [59]

Answer:

No.

Step-by-step explanation:

6^2=36

12^2=144

36/144 simplified is 1/4

6 0
2 years ago
Answer!!!!!!!!!!!!!!!!!
Ghella [55]

Answer:

Step-by-step explanation:

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8 0
1 year ago
X=-12-6y <br>-4x+5y=-39<br>slove by the system of substitution
Artist 52 [7]
X = -6y - 12
4x + 5y =-39

                  4x + 5y = -39
     -4(-6y - 12) + 5y = -39
-4(-6y) + 4(12) + 5y = -39
       24y + 48 + 5y = -39
               29y + 48 = -39
                       29y = -87
                            y = -3

x = -6y - 12
x = -6(-3) - 12
x = 28 - 12
x = 6

(x, y) = (6, -3)
5 0
3 years ago
In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.
Tema [17]

Answer:

Area  \approx 1149\ cm^2

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to \angle W)

Side u = 83 cm (It is the side opposite to \angle U)

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

A = \dfrac{1}{2}\times a\times b\times sinC

Where a and b are the two sides and

\angle C is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A  \approx 1149\ cm^2

So, the <em>area </em>of given triangle to the nearest square centimetre is:

Area  \approx 1149\ cm^2

8 0
3 years ago
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