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viva [34]
4 years ago
12

Does anyone know how to do Linear Equations? can anyone help me under stand them?

Mathematics
2 answers:
erica [24]4 years ago
6 0
Watch it will help you

Advocard [28]4 years ago
5 0

Answer:

yea what is it???

Step-by-step explanation:

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Evaluate the expression for c = -8 and d = 2. cd + d =
topjm [15]

c = -8 which means  whenever you see a c replace it with -8

d = 2 means the same for 2

and cd means c times d

so

cd + d

is

(-8)(2) + (2)    =

-16 + 2  = -14


7 0
3 years ago
Read 2 more answers
Find the equation of line that goes through coordinates (-4,-2) and (-3,-5) ?
frutty [35]

Answer: y = -3x/7 + 26/7

Step-by-step explanation: Using the "slope-intercept" format, we can set up 2 equations, using the given points.

The format:  y = mx + b, where m is the slope and b is the y-intercept (where x = 0)

To find m and b, we need 2 equations which we get using the 2 given points:

(-3,5):

5 = m(-3) + b  (equation 1)

(4,2):

2 = m(4) + b   (equation 2)

Subtract #2 from #1 to get:

3 = -7m

m = -3/7

Then, using equation 1, find b:

5 = (-3/7)*(-3) + b

b = 5 - 9/7 = 26/7

The equation is then:

y = -3x/7 + 26/7

3 0
2 years ago
1 Eddie drew the model below to represent an equation.
Paladinen [302]
The answer is D. Not here
5 0
3 years ago
Which images shows a reflection​
leonid [27]

I'll Give You Some Hints:

Let's Look at C.

In C, the triangle is translated 2 units to the right. Which means that it cannot be a reflection.

Let's Look at B.

In B there is a sideways triangle. That means it's a Rotation. Which means it's not Reflected.

Lastly, Let's Look at A.

To get from the original triangle to the triangle in A, you have to reflect twice. Once along a vertical line, and then along a horizontal line.

This Information Should Help You

7 0
3 years ago
Using what you know about right triangle trigonometry, salt the triangle round the side to the nearest 10th and angle measures t
Elden [556K]

Answer:

Angle A = 49°  Angle B = 41°  Side AB = 30.5

Step-by-step explanation:

Let's work out Angle A and Angle B first. We are given AC and CB, therefore AB must be the hypotenuse as it is the longest side.

AC and CB must be the opposite and adjacent sides, therefore we can use tan(x) = Opposite/Adjacent for working out both Angle A and Angle B.

Angle A:

tan(A) = 23/20  For Angle A, CB (23) is the side opposite the angle and AC (20) is the side in between Angle A and the right angle, also the adjacent side.

A = tan^{-1}(\frac{23}{20})  We do the inverse of tan here.

A = 48.9909131

A = 49°  Rounding to the nearest degree simply means to the nearest whole number.

Angle B:

tan(B) = 20/23  For Angle B, AC (20) is the side opposite the angle and CB (23) is the side in between Angle B and the right angle, also the adjacent side.

B = tan^{-1}(\frac{20}{23})

B = 41.0090869

B = 41°

Side AB:

We can just use Pythagoras' Theorem here to work out AB, but I will also use trigonometry to show you how you can use both formulas. When I use trigonometry, I will only be using Angle A as an example.

Pythagoras' Theorem: a^{2}  + b^{2}  = c^{2}

AC = 20 = a

CB = 23 = b

20^{2}  + 23^{2}  = c^{2}

929 = c^{2}

c = \sqrt{929}

c = 30.47950131

c = 30.5  Rounding to the nearest 10th simply means rounding to 1 decimal place.

Trigonometry: SOHCAHTOA

Angle A = 49°

AC = 20  I will use AC as our adjacent side instead of CB. They will both give us the same answer anyways.

AB will always be the hypotenuse in the given right-angled triangle.

cos(x) = Adjacent/Hypotenuse

cos(49) = 20/AB

ABcos(49) = 20  Here we multiply by AB, our hypotenuse.

AB = 20/cos(49)  Now we divide by cos(49)

AB = 30.48506173  As you can see here, this answer is different from the Pythagoras' Theorem one because we rounded our angle values, meaning out angle values aren't exact! Instead, use Pythagoras' Theorem here for more accurate results instead of Trigonometry.

AB = 30.5  They still give us the same answer in the end!

I hope this helps you!! ^-^

7 0
3 years ago
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