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Furkat [3]
3 years ago
14

Help me!

Mathematics
2 answers:
ella [17]3 years ago
7 0

\dfrac{a}{4}-\dfrac{5}{6}=-\dfrac{1}{2}\qquad\text{multiply both sides by common denominator 12}\\\\12\cdot\dfrac{a}{4}-12\cdot\dfrac{5}{6}=12\cdot\left(-\dfrac{1}{2}\right)\\\\3\cdot a-2\cdot5=6\cdot(-1)\\\\3a-10=-6\qquad\text{add 10 to both sides}\\\\3a=4\qquad\text{divide both sides by 3}\\\\\boxed{a=\dfrac{4}{3}=1\dfrac{1}{3}}

vlabodo [156]3 years ago
4 0

Answer:

a = 4/3

Step-by-step explanation:

a/4 - 5/6 + 5/6 = -1/2 + 5/6

a/4 = 1/3

4a/4 = 1 x 4/3

a = 4/3

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How can I factor 16x^2-44x+24?
Papessa [141]
16x² - 44x + 24
= 4(4x² - 11x + 6)
= 4(x * 4x - 8x - 3x + 2 * 3)
= 4(x - 2)(4x - 3)
8 0
3 years ago
R = sec(θ) − 2cos(θ), where -π/2 < θ < π/2
Alex

Answer:

  y = (x/(1-x))√(1-x²)

Step-by-step explanation:

The equation can be translated to rectangular coordinates by using the relationships between polar and rectangular coordinates:

  x = r·cos(θ)

  y = r·sin(θ)

  x² +y² = r²

__

  r = sec(θ) -2cos(θ)

  r·cos(θ) = 1 -2cos(θ)² . . . . . . . . multiply by cos(θ)

  r²·r·cos(θ) = r² -2r²·cos(θ)² . . . multiply by r²

  (x² +y²)x = x² +y² -2x² . . . . . . . substitute rectangular relations

  x²(x +1) = y²(1 -x) . . . . . . . . . . . subtract xy²-x², factor

  y² = x²(1 +x)/(1 -x) = x²(1 -x²)/(1 -x)² . . . . multiply by (1-x)/(1-x)

  \boxed{y=\dfrac{x\sqrt{1-x^2}}{1-x}}

__

The attached graph shows the equivalence of the polar and rectangular forms.

4 0
3 years ago
PLEASE HELP NEED ASAP WILL MARK THE BRAINLIEST
harkovskaia [24]

Answer:

idk

Step-by-step explanation:

idk

7 0
4 years ago
Using the traditional formula, a 95% CI for p1 − p2 is to be constructed based on equal sample sizes from the two populations. F
inn [45]

Answer:

49

Step-by-step explanation:

Given:

Width = 0.4

Let's take the z value of 95% which is = 1.96

Let's assume population proportion p1 and p2 = 0.5

For margin of error E, the relation between the width and margin of error is 2E.

i.e 2E = 0.4

E = 0.2

To find the sample size, n, let's use the formula :

n= \frac{z^2*(p_1(1-p_1) + p_2(1-p_2))}{E^2}

= \frac{1.96^2(0.5(1-0.5)+0.5(1-0.5))}{0.2^2}

= 48.02

≈ 49

8 0
4 years ago
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
avanturin [10]
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900

There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20

The price of an advance ticket was 20.
The price of a same-day ticket was 15.
6 0
4 years ago
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