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AnnZ [28]
3 years ago
7

How do the signs of b and c in standard form, x2 + bx + c, affect the signs of p and q in factored form, (x + p)(x + q)?

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
6 0

They affect the signs of p and q in different ways.

Firstly, if c is negative, it means that p and q have opposite signs.

If c is positive, then it means that p and q have the same signs. However, to determine whether they are both positive or both negative, we then have to look to b. If b is negative, both p and q would be negative. If b is positive, then both p and q are positive.

mart [117]3 years ago
5 0

Answer:

If b and c are positive,both p and q are positive,but if b and c are negative then p and q are negative too.

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c) 515502 samples

Step-by-step explanation:

a) How many ways sample of 5 each can be selected from 40 is just a combination problem since the order of selection isn't important.

So, the number of samples = ⁴⁰C₅ = 658008 samples

b) How many samples of 5 contain exactly one nonconforming chip?

There are 10 nonconforming chips in the batch, and 1 nonconforming chip for the sample of 5 be picked from ten in the following number of ways

¹⁰C₁ = 10 ways

then the remaining 4 conforming chips in a sample of 5 can be picked from the remaining 30 total conforming chips in the following number of ways

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c) How many samples of 5 contain at least one nonconforming chip?

The number of samples of 5 that contain at least one nonconforming chip = (Total number of samples) - (Number of samples with no nonconforming chip in them)

Number of samples with no nonconforming chip in them = ³⁰C₅ = 142506 samples

Total number of samples = 658008

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