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2 years ago

Find the 37th term of the arithmetic sequence: -38,-8,22,52

Mathematics

1 answer:

Leya [2.2K]2 years ago

3 0

Answer:

1042

Step-by-step explanation:

-38,-8,22,52

The common difference is 52 - 22 = 30

a_1 = -38

a_2 = -38 + 30

a_3 = -38 + 2 * 30

a_4 = -38 + 3 * 30 (notice that the common difference is multiplied by 1 less than the term number)

a_n = -38 + (n - 1)30 (since the term number is n, we multiply the common difference by n - 1)

a_n = -38 + 30(n - 1)

a_37 = -38 + 30(37 - 1)

a_37 = 1042

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2 years ago

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3 years ago

. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?

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Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

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Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

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Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).

Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).

Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

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2 years ago