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anzhelika [568]
2 years ago
11

Tom has 12 ears of field corn to make

Mathematics
1 answer:
Leviafan [203]2 years ago
5 0
Tom arranged 3 groups of 4
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allsm [11]

Answer:

yea

Step-by-step explanation:

4 0
3 years ago
Write inequalities to describe the solid left (x < 0 is left) hemisphere of a sphere of radius 4 centered at the origin
Serggg [28]
The equation of the sphere centered at 0, and radius 4 is:

\displaystyle{ x^2+y^2+z^2=4^2, 

note that this equation describes exactly the points of the surface of the square. That is, this is an EMPTY sphere.

The solid sphere, that is the points on the surface and all points in the inside, are given by :

\displaystyle{ x^2+y^2+z^2 \leq 4^2


since we want the left part of the solid part, picture 2, we add the condition x<0,


thus "the solid left (x < 0 is left) hemisphere of a sphere of radius 4 centered at the origin" is given by the system of inequalities:

i) \displaystyle{ x^2+y^2+z^2 \leq 4^2
ii)x\ \textless \ 0

8 0
3 years ago
Read 2 more answers
Ayo runs a fairground game.In each turn, a player rolls a fair dice numbered 1 - 6 and spins a fair spinner numbered 1 - 12.It c
aksik [14]

Using the definition of expected value, it is found that Ayo can be expected to make a profit of £55.8.

The <em>expected value</em> is given by the <u>sum of each outcome multiplied by it's respective probability.</u>

In this problem:

  • The player wins $6, that is, Ayo loses £6, if he rolls a 6 and spins a 1, hence the probability is \frac{1}{6} \times \frac{1}{12} = \frac{1}{72}.
  • The player wins $3, that is, Ayo loses £3, if he rolls a 3 on at least one of the spinner or the dice, hence, considering three cases(both and either the spinner of the dice), the probability is \frac{1}{6} \times \frac{1}{12} + \frac{1}{6} \times \frac{11}{12} + \frac{5}{6} \times \frac{1}{12} = \frac{1 + 11 + 5}{72} = \frac{17}{72}
  • In the other cases, Ayo wins £1.40, with 1 - \frac{18}{72} = \frac{54}{72} probability.

Hence, his expected profit for a single game is:

E(X) = -6\frac{1}{72} - 3\frac{17}{72} + 1.4\frac{54}{72} = \frac{-6 - 3(17) + 54(1.4)}{72} = 0.2583

For 216 games, the expected value is:

E = 216(0.2583) = 55.8

Ayo can be expected to make a profit of £55.8.

To learn more about expected value, you can take a look at brainly.com/question/24855677

6 0
2 years ago
Seven friends bought pizza. Each friend pitched in the same amount. If the pizza came to a total of $14.49, how much did each fr
Svet_ta [14]
Each friend payed $2.07
8 0
3 years ago
Read 2 more answers
You roll a 6-sided die. What is P(prime)? Write your answer as a percentage.
netineya [11]

Answer:

50%

Step-by-step explanation:

7 0
2 years ago
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