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kumpel [21]
2 years ago
8

Can someone help me out on these geometry questions? ASAP!!!

Mathematics
1 answer:
zaharov [31]2 years ago
8 0

<u>Question 6</u>

1) \overline{AB} \cong \overline{BD}, \overline{CD} \perp \overline{BD}, O is the midpoint of \overline{BD}, \overline{AB} \cong \overline{CD} (given)

2) \angle ABO, \angle ODC are right angles (perpendicular lines form right angles)

3) \triangle ABO, \triangle CDO are right triangles (a triangle with a right angle is a right triangle)

4) \overline{BO} \cong \overline{OD} (a midpoint splits a segment into two congruent parts)

5) \triangle ABO \cong \triangle CDO (LL)

<u>Question 7</u>

1) \angle ADC, \angle BDC are right angles), \overline{AD} \cong \overline{BD}

2) \overline{CD} \cong \overline{CD} (reflexive property)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \triangle ADC \cong \triangle BDC (LL)

5) \overline{AC} \cong \overline{BC} (CPCTC)

<u>Question 8</u>

1) \overline{CD} \perp \overline{AB}, point D bisects \overline{AB} (given)

2) \angle CDA, \angle CDB are right angles (perpendicular lines form right angles)

3) \triangle CDA, \triangle CDB are right triangles (a triangle with a right angle is a right triangle)

4) \overline{AD} \cong \overline{DB} (definition of a bisector)

5) \overline{CD} \cong \overline{CD} (reflexive property)

6)  \triangle ADC \cong \triangle BDC (LL)

7) \angle ACD \cong \angle BCD (CPCTC)

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Shtirlitz [24]

false

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2/10=1/5

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3 years ago
A rectangular yoga mat has a perimeter of 179 inches. The width of the mat is eight less than half the length. Find the width, i
lianna [129]

Answer:

The width is 24.5in

Step-by-step explanation:

The perimeter of the rectangular yoga mat can be found using the formula;

P=2l+2w.

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It was given that the width of the mat is eight less than half the length.

w=\frac{1}{2}l-8...(2)

We put equation (2) into equation (1) to get;

179=2l+2(\frac{1}{2}l-8).

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Divide both sides by 3;

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We put l=65 into equation 2 to get;

w=\frac{1}{2}\times65-8

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3 years ago
Can you guys help? I got this, and I want to divide the parts in eighths? What fraction is it? HELP MEEE!!!! IM NOT A SMART DUDE
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First draw a line in the middle of your box vertically. Then draw a horizontal line that is also in the middle of your box and then draw another line above the horizontal line and below the horizontal line in between the two boxes you made I added a picture below to show. The fraction is 1/8

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