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3 years ago

Please help me answer this question: (D 3, 3, 5, 5, 6, 7, 8, 9, 11

Mathematics

1 answer:

elixir [45]3 years ago

5 0

Answer:

According to the graph presented within the proposed interrogate, the answer to such is identified as ‘C’: 2, 3, 5, 5, 6, 7, 8, 10, 11.

Step-by-step explanation:

To evaluate for such a problem, a comprehension of the “Whisker” plots is obligated.

- The box geometric figure with the vertical line contained within represents the average of the numbers presented.

* In this peculiar case, 6 is acknowledged as the individual value responsible for the mean.

Thus far, browsing at such answer choices, we are obligated to appoint an answer where 6 is the standard deviation or the mean (where 6, and only 6, is found in the middle of the set of numbers provided).

The only answer choice in which certifies to all conditions thus far declared is disseminated as “C”.

*I hope this helps.

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Answer:

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Step-by-step explanation:

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3 years ago

A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f

tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

= 180° - (45° + 120°)

= 180° - 165°

= 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

$\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}$

$\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}$

$\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}$

PR = $\frac{12\text{sin}(120)}{\text{sin}(15)}$

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

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3 years ago

Number 3 and 4 please ASAP

Tpy6a [65]

Step-by-step explanation:

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540 + 180 + 180 = 900 books in 5 hours

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