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NISA [10]
2 years ago
10

a family has 8 girls and 4 boys. a total of 3 children must be chosen to speak on behalf of their family at a local benefit. wha

t is the probability that no girls and 3 boys will be chosen help quickly someone
Mathematics
1 answer:
Nina [5.8K]2 years ago
8 0

Answer:

1/55

Step-by-step explanation:the probability of choosing 3 boys.

The probability of choosing the first boy =4/12

The probability of choosing the second boy =3/11

The probability of choosing the third boy =2/10

The probability of choosing the 3 boys will be,

=4/12×3/11×2/10

=24/1320

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\bf \measuredangle 1=\cfrac{x-32}{2}\implies \measuredangle 1 =\cfrac{32}{2}\implies \measuredangle 1 = 16 \\\\[-0.35em] ~\dotfill\\\\ \measuredangle 5 =\cfrac{2x}{2}\implies \measuredangle 5 = x\implies \measuredangle 5 = 64 \\\\[-0.35em] ~\dotfill

\bf \measuredangle 2 = \cfrac{(2x+8)~~-~~(x-32)}{2}\implies \measuredangle 2=\cfrac{2x+8-x+32}{2} \\\\\\ \measuredangle 2=\cfrac{x+40}{2}\implies \measuredangle 2=\cfrac{104}{2}\implies \measuredangle 2=52 \\\\[-0.35em] ~\dotfill\\\\ \measuredangle 6=\cfrac{[(2x+8)+(x)]~~-~~(2x)}{2}\implies \measuredangle 6=\cfrac{3x+8-2x}{2}\implies \measuredangle 6=\cfrac{x+8}{2} \\\\\\ \measuredangle 6=\cfrac{72}{2}\implies \measuredangle 6=36

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