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NISA [10]
2 years ago
10

a family has 8 girls and 4 boys. a total of 3 children must be chosen to speak on behalf of their family at a local benefit. wha

t is the probability that no girls and 3 boys will be chosen help quickly someone
Mathematics
1 answer:
Nina [5.8K]2 years ago
8 0

Answer:

1/55

Step-by-step explanation:the probability of choosing 3 boys.

The probability of choosing the first boy =4/12

The probability of choosing the second boy =3/11

The probability of choosing the third boy =2/10

The probability of choosing the 3 boys will be,

=4/12×3/11×2/10

=24/1320

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Step-by-step explanation:

3 0
3 years ago
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5.5% sales tax on a 59.99 lamp
VikaD [51]

Answer:

$63.29

Step-by-step explanation:

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there i hope i help :)

7 0
3 years ago
How much more area does a large pizza with a 12 in. diameter have than a small pizza with an 8 in. diameter? Round your answer t
ivolga24 [154]

Answer: About 63 in²

Step-by-step explanation:

<u>Area of circle = π · r²</u>

  • r = radius length
  • π ≈ 3.14

<u>Area of large pizza:</u>

\pi *r^{2} =3.14*6^{2} =3.14*36=113.04

<u>Area of small pizza:</u>

\pi *r^{2} =3.14*4^{2} =3.14*16=50.24

<u>Difference in area:</u>

113.04-50.24=62.8

4 0
2 years ago
Kelly purchased 5 containers of ice cream for a party. Each container holds 8 cups of ice cream. Before the party, her brother a
victus00 [196]

Given:

Kelly purchased 5 containers of ice cream for a party.

Each container holds 8 cups of ice cream.

Her brother ate 2 cups of ice cream.

One serving of ice cream = 2/3 of a cup.

To find:

Number of servings of ice cream will be left for the party?

Solution:

We have,

1 container = 8 cups of ice cream

5 containers = 5×8 = 40 cups of ice cream

Her brother ate 2 cups of ice cream. So, remaining cups of ice cream is

40-2=38 cups

Now,

\dfrac{2}{3} of a cup = 1 serving

1 cup = \dfrac{3}{2} serving

38 cup = 38\times \dfrac{3}{2} serving

            = 19\times 3 serving

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Therefore, 57 servings of ice cream will be left for the party.

4 0
3 years ago
What is the sum of 5x^2y and (2xy^2 + x^2y)
eimsori [14]
Recognize that you must combine "like" terms.  5x^2y and x^2y are "like" terms.

Adding them together, you get 6x^2y.  

Now add 2xy^2 to 6x^2y.  These are NOT "like" terms, so you end up with 
6x^2y+2xy^2 as your final answer.  This answer is acceptable as is.  

However, you could factor out the common factors:  2xy(3x+y).
8 0
3 years ago
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