Answer:[m, m+d, m+2d, - - - - -, n]
Step-by-step explanation:
We know the formula for arithmetic progression is a_(n) = a_(1) + (n-1)d
Where a_(n) is the nth term of the sequence
a_(1) is the first term of the sequence
n is the number of the term like if we are talking about 7th term so the n is 7.
d is the difference between two successive terms.
For this problem we know our first term that is m, our last term that is n and our difference that is d.
For second term we will use the formula
a_(2) = m + (2-1)d
a_(2) = m + (1)d
a_(2) = m + d
Similarly,
a_(3) = m + (3-1)d
a_(3) = m + (2)d
a_(3) = m + 2d
Answer:

Step-by-step explanation:
Hello!
A linear function is written in the form of
, where m is the slope and b is the y-intercept.
Each of these expressions can be converted to coordinate form, (-2,9) and (6,7).
<h2>Slope</h2>
Slope can be calculated by the difference in the x-values divided by the difference in the y-values.
Solve
The slope is -1/4.
<h2 /><h2>Y-intercept</h2>
The y-intercept is found by plugging in the x and y values of a coordinate and the slope and then solving for b.
Solve
<h2>Equation</h2>
We can find the equation by simply plugging in all the values that we found.
Equation: 
$367.80 because you have to add up the purchase the owe and the other one too, then you get your answer
<u>Answer:</u>
The amount lost over the 3 years s 2567.25£
<u>Explanation:</u>

where F = final value after n years
I = initial value of the car in 2017 = £18000 (given)
Since the value is depreciated 5% every year for 3 years,
r = percentage rate of depreciation = 5% (given)
n = 3 years
Substituting these values in formula, we get

=

= 15432.75£ which is the value of the car after 3 years
Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.
Answer:
c. f(x) x+1/x-1
Step-by-step explanation:
To answer this question, we need to check each answer one by one until we find the right one.
y = (x+6)/(x-6)
switch x and y
x = (y+6)/(y-6)
solve for y
x(y-6) = y+6
xy - 6x = y+6
y(x-1) = 6x+6
y = (6x+6) /(x-1) = 6(x+1)/(x-1)
f^-1(x) = 6(x+1)/(x-1)
y = (x+2)/(x-2)
switch x and y
x = (y+2)/(y-2)
solve for y
x(y-2) = y+2
xy -2x = y+2
y(x-1) = 2x+2
y = (2x+2)/(x-1)
f^-1(x) = 2(x+1)/(x-1)
y = (x+1)/(x-1) ------ correct one
switch x and y
x = (y+1)/(y-1)
solve for y
x(y-1) = y+1
xy - x = y+1
y(x-1) = x+1
y = (x+1)/(x-1)
f^-1(x) = (x+1)/(x-1)
f(x) = f^-1(x)