a = 5 in
b = 12 in
c = 15 in
the lengths of the sides a, b and c
the perimeter is P = a + b + c = 5 + 12 + 15 = 32 in
let the dimensions of the new triangle be
a1 = (1/5)*5 in
b1 = (1/5)*12 in
c1 = (1/5)*15 in
the perimeter is P1 = a1 + b1 + c1 = (1/5)5 + (1/5)12 + (1/5)15 = (1/5)(5 + 12 + 15) = (1/5)P1
P1 = (1/5)P
P1/P = 1/5 = a/a1 = b/b1 = c/c1
the ratio of the perimeters is equal to the ratio of the corresponding sides.
Answer:
it would be 3 8/10
Step-by-step explanation:
you have to find a common multiple and it would be 10 thin you add them up 7/10+1/10=8/10 plus you have to put the 3 with the 8/10
Answer:
Option A- One
Step-by-step explanation:
Given that : The sides of the triangle measuring 6cm, 2cm and 7cm.
We are using : Triangle inequality
The sum of the length of the two sides should be greater than the length of the third side.
So, when we apply this theorem in 6cm,2cm and 7cm
6+2=8>7 , 7+2=9>6 , 7+6=13>2
It satisfy all three possible sets.
Therefore, the given values follows the triangle inequality.
Hence one triangle can be formed.
Therefore, option A is correct.
Answer:
2200
Step-by-step explanation:
The variable in this formula is x and the number on it's side is 2200.
The third option is correct