Question

Find the zeros of the function. Write the smaller solution first, and the larger solution second. f(x)=-3x^2 +75f(x)=−3x 2 +75f, left parenthesis, x, right parenthesis, equals, minus, 3, x, squared, plus, 75 \text{smaller }x =smaller x=start text, s, m, a, l, l, e, r, space, end text, x, equals \text{larger } x =larger x=start text, l, a, r, g, e, r, space, end text, x, equals

Answer 1

Answer:

• Smaller x= -5
• Larger x=5

Step-by-step explanation:

Given the function $f(x)=-3x^2 +75$

The zeros of the function are the values of x for which f(x)=0.

$f(x)=-3x^2 +75=0\\-3x^2 +75=0\\-3(x^2-25)=0\\ Divide both sides by -3\\x^2-25=0\\ Add 25 to both sides\\x^2-25+25=0+25\\x^2=25\\ Take the square root \\\sqrt{x^2}=\pm \sqrt{25}\\ x=\pm 5$

The zeros of f(x) are therefore 5 and -5.

• Smaller x= -5
• Larger x=5