A company's cost formula for its salaries and wages cost is $2,850 per month plus $317 per job. For the

Mathematics

1 answer:

GuDViN [60]2 years ago

7 0

The spending variance for salaries and wages cost in February would be closest to; $282 F.

<h3>What is the spending variance in February?</h3>

The spending variance as the name implies is the difference between the budgeted cost and actual cost paid for an item. It therefore follows from the definition above that for the month of February;

Spending variance = $7,640 - (2850 + (16×317))

Spending variance = $7,640 - (7922)

Spending variance is therefore; $282 F.

You might be interested in

Question is in picture

ElenaW [278]

Answer:

hypotenuse = 102.69

Step-by-step explanation:

7(13) + 4 = 95

3(13) = 39

hypotenuse² = 95² + 39² = 9025 + 1521 = 10546

hypotenuse = √10546 = 102.69

5 0

3 years ago

Read 2 more answers

1. This table shows the input and output values for an exponential function f(x).

aleksklad [387]

Answer:

Question 1) Is option C: 2. (Question 2) The correct answer is 1.09 for the K12 program. Question 3) Option A: The value of a motorcycle decreases by 12% each year. (Option C) Every year, the number of online subscribers to a service is 4 times what it was the previous year.

8 0

3 years ago

The distribution of results from a cholesterol test has a mean of 180 and a standard deviation of 20. A sample size of 40 is dra

olga2289 [7]

Using the normal distribution, there is a 0.2148 = 21.48% probability that the sum of the 40 values is less than 7,100.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For this problem, these parameters are given as follows:

$\mu = 180, \sigma = 20, n = 40, s = \frac{20}{\sqrt{40}} = 3.1623$

A sum of 7100 is equivalent to a sample mean of 7100/40 = 177.5, which means that the probability is the <u>p-value of Z when X = 177.5</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem:

$Z = \frac{X - \mu}{s}$