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larisa86 [58]
2 years ago
7

A company's cost formula for its salaries and wages cost is $2,850 per month plus $317 per job. For the

Mathematics
1 answer:
GuDViN [60]2 years ago
7 0

The spending variance for salaries and wages cost in February would be closest to; $282 F.

<h3>What is the spending variance in February?</h3>

The spending variance as the name implies is the difference between the budgeted cost and actual cost paid for an item. It therefore follows from the definition above that for the month of February;

Spending variance = $7,640 - (2850 + (16×317))

Spending variance = $7,640 - (7922)

Spending variance is therefore; $282 F.

Read more on spending variance;

brainly.com/question/25801623

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A computer sells for $610. It is now on sale for 1/5 off the original price. Derek has a coupon for an extra 10% off the sale pr
belka [17]

Derek will  pay $625.25 less than the original prize

<u>Step-by-step explanation:</u>

The selling price of the computer=$610

The selling prize is 1/5 of its original prize

Derek has a 10% off coupon

Let the original prize of the computer=x

selling prize=x-x/5

4x/5=610

4x=3050

x=3050/4=762.5

The\ prize\ at\ which\ Derek\ will\ buy\ the\ computer=x \times 1/5 \times (100-10)/100\\=x\times 1/5 \times 90/100\\=9x/50\\

the difference in the original prize and the prize at which Derek bought the computer=x-9x/50

=41x/50

41 \times 762.5/50\\=$625.25

Derek will pay $625.25 less than the original price for the computer.

8 0
3 years ago
A Ferris wheel is 23 meters in diameter and boarded from a platform that is 3 meter
sladkih [1.3K]
I took your mom from the shelter
7 0
3 years ago
CAN SOMEONE HELP I WILL MARK BRAINLIEST
disa [49]

<u>First row:</u> PERCENT: 140% FRACTION: 7/5 DECIMAL: 1.4

<u>Second row:</u> PERCENT: 4% FRACTION: 1/25 DECIMAL: 0.04

<u>Third row</u>: PERCENT: 56% FRACTION:14/25 DECIMAL: 0.56

<u>Fourth row:</u> PERCENT: 95% FRACTION: 19/20 DECIMAL: 0.95

Hope this helps.

8 0
3 years ago
Read 2 more answers
HELP PLS
Snezhnost [94]

Answer:

a loss of 72.47

Step-by-step explanation:

I got this answer right on my test

6 0
3 years ago
find the value of "a" and "b" for which the limit exists both as x approaches 1 and as x approaches 2:
lbvjy [14]

Answer:

a = 4

b = -2

Step-by-step explanation:

If the given function is continuous at x = 1

\lim_{x \to 1^{-}} f(x)=(x+1)

                     =2

\lim_{x \to 1^{+}} f(x)=ax+b

                     =a+b

\lim_{x \to 1} f(x)=ax+b

                   =a+b

And for the continuity of the function at x = 1,

\lim_{x \to 1^{-}} f(x)=\lim_{x \to 1^{+}} f(x)=\lim_{x \to 1} f(x)

Therefore, (a + b) = 2 -------(1)

If the function 'f' is continuous at x = 2,

\lim_{x \to 2^{-}} f(x)=ax+b

                     =2a+b

\lim_{x \to 2^{+}} f(x)=3x

                     =6

\lim_{x \to 2} f(x)=3x

                   =6

Therefore, \lim_{x \to 2^{-}} f(x)=\lim_{x \to 2^{+}} f(x)=\lim_{x \to 2} f(x)

2a + b = 6 -----(2)

Subtract equation (1) from (2),

(2a + b) - (a + b) = 6 - 2

a = 4

From equation (1),

4 + b = 2

b = -2

3 0
3 years ago
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